counter

1 不仅可以统计list中元素的出现次数,也可以对str中的元素进行统计 # collections包中的Counter用于统计str list 中元素出现次数 from collections import Counter a = [1,1,2,3,4,5,6,6,6] b = Counter(a) # 输出一个a中每个元素出现次数的类,且按出现次数由高到低排列 print(b) # 输出元素5的出现次数 print(b[5]) # 输出出现次数前三的(元素,次数)对,且类型是list print(b.most_common(3)) # Counter({6: 3, 1: 2, 2: 1, 3: 1, 4: 1, 5: 1}) # 1 # [(6, 3), (1, 2), (2, 1)] # 如下直接输出元素按出现次数由高到低的排序,用的most_common()目的是将Counter(a)化为list,便于迭代 print([item for items, c in Counter(a).most_common() for item in [items] * c]) # [6, 6, 6, 1, 1, 2, 3, 4, 5] View Code 参考:http://www.aiisen.com/p/1166376.html 来源： https://www.cnblogs.com

This question already has answers here : Animate counter when in viewport (3 answers) Closed 3 years ago . I'm trying to make a number count up when it's within the viewport, but currently, the script i'm using will interrupt the count on scroll. How would I make it so that it will ignore the scroll and just count up when it's within the viewport? This needs to work on mobile, so even when a user is scrolling on touch. It cannot interrupt the count. Please see here: http://jsfiddle.net/Q37Q6/27/ (function ($) { $.fn.visible = function (partial, hidden) { var $t = $(this).eq(0), t = $t.get(0),

I have a dataframe with sentences and a dictionary of terms grouped into topics, where I want to count the number of term matches for each topic. import pandas as pd terms = {'animals':["fox","deer","eagle"], 'people':['John', 'Rob','Steve'], 'games':['basketball', 'football', 'hockey'] } df=pd.DataFrame({ 'Score': [4,6,2,7,8], 'Foo': ['The quick brown fox was playing basketball today','John and Rob visited the eagles nest, the foxes ran away','Bill smells like a wet dog','Steve threw the football at a deer. But the football missed','Sheriff John does not like hockey'] }) So far I have created

I would like to quickly build a word look-up table for a corpus with nltk. Below is what I am doing: Read raw text: file=open("corpus","r").read().decode('utf-8') Use a=nltk.word_tokenize(file) to get all tokens; Use set(a) to get unique tokens, and covert it back to a list. Is this the right way of doing this task? Try: import time from collections import Counter from nltk import FreqDist from nltk.corpus import brown from nltk import word_tokenize def time_uniq(maxchar): # Let's just take the first 10000 characters. words = brown.raw()[:maxchar] # Time to tokenize start = time.time() words =

I described my original problem in this thread . In short, when using custom counters in ULs, the text indentation broke. Marc Audet proposed a very elegant solution which I implemented in our code. Now - not surprising - this does not work if the list is supposed to float around images :-( You can see the problem here: http://cssdesk.com/eEvwn The numbers are lying on top of the image. Again: no surprise, they are absolutely positioned after all. So. Is there a way to fix this, or do I have to make my client unhappy by telling him it's technically not possible? Thank you again for taking the

I am trying to complete a task and I am unsure what route to take. I have tried while , if , and a combination of statements and cannot get the input validation I need. I am trying to validate user input and ensure their input is a number between 0 and 10 (excluding 0 and 10). Also I need to make sure that what they do enter is a number and not some symbol or letter. Finally I need a counter that will allow them 3 chances to input the correct information. The code below is my method I am trying to setup to accomplish this. private static int getNumericInput(String quantity) { int count = 0;

So, we were given this program in class. "Write a Program in C to count the number of words in a sentence input by the user." This is what i could come up with, but the number of words is always one less than what is the correct number. My teacher told everyone to just add 1 to the word count before printing it. I think it has a bug, if we don't enter any words, i.e. , press Enter instead of typing,the program suggested by my teacher would still give word count as 1 not 0. Do you know of any way to get proper word count without just adding 1 at the end? Code: My code(giving 1 less than correct

My Professor wants me to this: Write a number of interchangeable counters using the Counter interface below public interface Counter { /** Current value of this counter. */ int value(); /** Increment this counter. */ void up(); /** Decrement this counter. */ void down(); } Develop the following: An interface ResetableCounter that supports the message void reset() in addition to those of Counter. Here's what I did: public interface ResetableCounter { void reset(); int value(); void up(); void down(); } An implementation of ResetableCounter called BasicCounter that starts at the value 0 and