coordinates

Convert unknown Hex digits to a Longitude and Latitude

ε祈祈猫儿з 提交于 2019-12-04 12:51:50
F3 c8 42 14 - latitude //05.13637° should be nearby this coordinate 5d a4 40 b2 - longitude //100.47629° should be nearby this coordinate this is the hex data i get from GPS device, how to convert to readable coordinate? i don't have any manual document.please help.thanks 22 00 08 00 c3 80 00 20 00 dc f3 c8 42 14 5d a4 40 b2 74 5d 34 4e 52 30 39 47 30 35 31 36 34 00 00 00 this is my full bytes i received,but the engineer told me that F3 c8 42 14 is latitude and 5d a4 40 b2 is longitude I think the values are in 32-bit floating point. However, the bytes are slightly shifted in the stream that

Placing child window relative to parent in Tkinter python

一世执手 提交于 2019-12-04 11:07:55
I have a parent widget which contains a button. When the button is pressed I would like to open a borderless (i.e. no Windows decoration buttons) window directly underneath the parent widget aligned to the left hand side of it. I'm puzzled that the only way (it seems) of setting the position of a window is using .geometry() but worse, I can't seem to get the absolute coordinates of the parent widget - which I need for .geometry() , only the offsets from the parent's parent. So far my code is: # This is the child which appears when the button is pressed. class ChildPopUpWindow(Frame): def _

Cubic bezier curve segment

随声附和 提交于 2019-12-04 10:41:08
If I have the 4 points describing a Bezier curve P1, P2, P3, P4 (where P1 and P4 are the end points of the curve and P2 and P3 are the control points of the curve), how could I find the points that describes only a segment of this bezier curve? I found this answer which is exactly what I am looking for but the answer seems wrong. If I set t0=0 and t1=1 in the equations which should represent the entire bezier curve, the resulting points are not valid. They are not equal to the original points. It seems that the solution is related to the De Casteljau's algorithm, but I can't understand how it

How do I convert these coordinates to coordinates readable by Google Maps?

空扰寡人 提交于 2019-12-04 09:25:22
问题 Take a look at the map coordinates on this page. This is linked in from Wikipedia and the coordinates are passed the query string. I'm not sure of the actual terms for this but How do I convert the coordinates? They look like this: 37° 14′ 6″ N, 115° 48′ 40″ W I would like them to look like this: 37.235, -115.811111 , which is a format readable by Google maps, as seen in this example. How do I do this in PHP, and what are the two different types of coordinates called? 回答1: The original format

Android - How to determine whether coordinates lie on road in Google Maps

拟墨画扇 提交于 2019-12-04 08:02:35
I need to make a check in my application that determines whether the given coordinates lie on road or not in Google Maps. Is there any function in Google Maps API that can aid me with that? Thanks in advance! As far as I know this can't be done using the Google Maps API. I think your best bet is to use a crowd-sourced dataset such as OpenStreetMap (OSM) . You'd need to set up your own spatial database (e.g., PostGIS ) and import OSM data into the database. Then, you'd create a server-side API (hosted in a web server such as Tomcat or Glassfish ) to receive the mobile phone's current location,

OpenGL coordinates to match screen coordinates?

扶醉桌前 提交于 2019-12-04 07:43:36
Android opengl-es view question. So in openGL, the default position of the camera and view is at 0,0. How do you set the view and camera so that it acts basically the same as computer screen coordinates with 0,0 at the top. I've called gl.glOrthof(-screenWidth/2, ScreenWidth/2, -ScreenHeight/2, ScreenHeight/2). But I think this is wrong. I also need to set the camera to view the entire field. I'm not sure how to use gl.glFrustumf to accomplish this task. To use your vertex coordinates as screen coordinates, just use glOrtho(0, width, height, 0, -1, 1) on the projection matrix and keep your

Plotting a list of (x, y) coordinates in python matplotlib

╄→гoц情女王★ 提交于 2019-12-04 07:27:19
问题 I have a list of pairs (a, b) that I would like to plot with matplotlib in python as actual x-y coordinates. Currently, it is making two plots, where the index of the list gives the x-coordinate, and the first plot's y values are the a s in the pairs and the second plot's y values are the b s in the pairs. To clarify, my data looks like this: li = [(a,b), (c,d), ... , (t, u)] I want to do a one-liner that just calls plt.plot() incorrect. If I didn't require a one-liner I could trivially do:

Covering Earth with Hexagonal Map Tiles

痞子三分冷 提交于 2019-12-04 07:24:07
问题 Many strategy games use hexagonal tiles. One of the main advantages is that the distance between the center of any tile and all its neighboring tiles is the same. I was wondering if anyone has any thoughts on marrying a hexagonal tile system with the traditional geographic system (longitude/latitude). I think it would be interesting to cover a globe with hexagonal tiles and be able to map a geographic coordinate to a tile. Has anyone seen anything remotely close to this before? UPDATE I'm

How to remove points that are far from a segment?

半世苍凉 提交于 2019-12-04 06:29:43
问题 I read how to keep points that are between two points (ie. : that are part of a segment, with some imprecision) here : How can I tell if a point is nearby a certain line? Thus, I implemented this little algorithm in Java, and my code is (note that the variables' name should be clear for you ! :) ) : List<Cupple> returned = new ArrayList<>(points_to_test); for(Cupple c : points_to_test) { /*if(c == segment_first_point || c == segment_last_point) { continue; }*/ if(Math.abs(Math.abs( (segment

Formula/algorithm to offset GPS coordinations

為{幸葍}努か 提交于 2019-12-04 06:24:18
问题 I have GPS coordinates provided as degrees latitude, longitude and would like to offset them by a distance and an angle. E.g.: What are the new coordinates if I offset 45.12345 , 7.34567 by 22km along bearing 104 degrees ? Thanks 回答1: For most applications one of these two formulas are sufficient: "Lat/lon given radial and distance" The second one is slower, but makes less problems in special situations (see docu on that page). Read the introduction on that page, and make sure that lat/lon