coordinates

Offset LatLng by some amount of meters in Android

我的未来我决定 提交于 2019-12-05 09:08:51
I have a LatLng object and I want to shift it's coordinates 500 meters to the east. I couldn't find a built-in method for that. I've seen https://gis.stackexchange.com/a/2964 but my results are just too inaccurate (about 15%) to use practically. How can I make a precise shift in meters? Note: I am NOT looking for shifting a Google Maps camera, I know how to do that. I've tried: static final double KILOMETERS_PER_DEGREE = 111.111; static LatLng offsetLongitude(LatLng initialCoords, float horizontalOffsetInMeters){ double degreeOffset = 1.0 / KILOMETERS_PER_DEGREE * horizontalOffsetInMeters /

3D coordinates as the output of a Neural Network

爱⌒轻易说出口 提交于 2019-12-05 07:48:33
问题 Neural Networks are mostly used to classify. So, the activation of a neuron in the output layer indicates the class of whatever you are classifying. Is it possible (and correct) to design a NN to get 3D coordinates? This is, three output neurons with values in ranges, for example [-1000.0, 1000.0], each one. 回答1: Yes. You can use a neural network to perform linear regression, and more complicated types of regression, where the output layer has multiple nodes that can be interpreted as a 3-D

How do I match similar coordinates using Python?

北城余情 提交于 2019-12-05 07:42:20
Background: I have been given four catalogues of data, the first of which (let's call Cat1) gives the coordinates (in right ascension and declination, RA and Dec) for radio sources in fields 1 and 2, the second catalogue (Cat2) gives the RA and Dec for radio sources and infrared (IR) sources in field 1, the third catalogue (Cat3) gives the RA and Dec for radio and IR sources in field 2, and the fourth catalogue (Cat4) gives the RA and Dec for optical sources in fields 1 and 2. Cat1 has approximately 2000 sources for field 2, keeping in mind that some of the sources are actually measured

Fuzzy matching of coordinates

本小妞迷上赌 提交于 2019-12-05 07:18:42
问题 I have two datasets, one of them containing the coordinates of people's addresses ( addresses ), and the other one containing the coordinates of rainfall in certain locations ( rain ). The coordinates are standard lat and lon. I would like to merge these two sets together, by matching each address to the nearest rainfall location, using the spherical distance between two coordinates to determine the "nearest". The naive way is to compute all pairwise distances between each address and each

how can I send coordinates to parse and save it as parse PFGeopoint

烈酒焚心 提交于 2019-12-05 06:44:17
问题 How can i send coordinates to Parse fetched by CLLocation and save it there as PFGeoPoint's latitude and longitude? I am able to get the coordinates from CLLocation and I want to send it to Parse. In Parse I have a column named "coordinates" of type PFGeoPoint which has two fields.Now I want to save the coordinates which I have got from CLLocation to Parse Column coordinates. can anyone please help me with this? I am new to iOS and Parse. 回答1: Two steps: Convert CLLocation to PFGeoPoint /

How to use weather api in c# [closed]

巧了我就是萌 提交于 2019-12-05 06:14:49
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 7 years ago . I want to implement weather information which will show me results that depends on my longitude and latitude. My app is getting coordinates from GPS so getting them is not a problem. Only thing is, I want to show some weather information for the city that is nearest me and that it has weather info. Can you give

Use X,Y coordinates to plot points inside a circle

霸气de小男生 提交于 2019-12-05 05:50:29
Is there a way in javascript to plot x,y coordinates so they fall into a circle rather than a square? For example if I have the following code: circleRadius = 100; context.drawImage(img_elem, dx, dy, dw, dh); I need to figure out a combination of x,y values that would fall inside a 100 pixel circle. Thanks! nico choose an x at random between -100 and 100 a circle is defined by x^2 + y^2 = r^2 , which in your case equals 100^2 = 10000 From this equation you can get that y^2 = 10000 - x^2 , therefore the points with a chosen x and y = +/-sqrt(10000 - x^2) will lye on the circle. choose an y at

Numpy matrix of coordinates

Deadly 提交于 2019-12-05 05:46:21
I'm trying to get a matrix of coordinate-arrays. This is different from numpy.meshgrid. For example, for a 2x2 size I'd want the 2x2x2 output [[[0,0],[0,1]], [[1,0],[1,1]]] as a numpy array. This probably looks and reads cleaner a 2x2 matrix of tuples: [[(0,0),(0,1)], [(1,0),(1,1)]] (except I don't think you can have tuples in a numpy array, and it's not the point here) This simple example can be done by switching the axes of numpy-meshgrid's output (specifically, moving the first axis to be last): np.array(np.meshgrid([0,1],[0,1])).transpose([1,2,0]) This could be easily generalized to

Size and position of one image in another via PHP

蓝咒 提交于 2019-12-05 05:36:31
问题 I have two images(small and big). Big one contains a small one. Like if the small one is a photo and a big one is a page from the photo album. How do I get coordinates of that small image in the big one using PHP? And also I need to know the size of that image in big one...so just a(x,y) coordinate of any angle and sizes of sides of that presentation of the small image... (x,y, width, height) I've already asked the question like that and got a brilliant answer (here) but I've forgot to

Handling touch events in a 3D “scene” or Screen to 3D coordinates

不问归期 提交于 2019-12-05 04:11:01
问题 I'm trying to implement a "whack-a-mole" type game using 3D (OpenGL ES) in Android. For now, I have ONE 3D shape (spinning cube) at the screen at any given time that represents my "mole". I have a touch event handler in my view which randomly sets some x,y values in my renderer, causing the cube to move around (using glTranslatef()). I've yet to come across any tutorial or documentation that completely bridges the screen touch events to a 3D scene. I've done a lot of legwork to get to where I