coordinate-systems

Changing the Coordinate System in LibGDX (Java)

那年仲夏 提交于 2019-11-27 00:08:49
LibGDX has a coordinate system where (0,0) is at the bottom-left. (like this image: http://i.stack.imgur.com/jVrJ0.png ) This has me beating my head against a wall, mainly because I'm porting a game I had already made with the usual coordinate system (where 0,0 is in the Top Left Corner). My question: Is there any simple way of changing this coordinate system? If you use a Camera (which you should) changing the coordinate system is pretty simple: camera= new OrthographicCamera(Gdx.graphics.getWidth(), Gdx.graphics.getHeight()); camera.setToOrtho(true, Gdx.graphics.getWidth(), Gdx.graphics

Python conversion between coordinates

女生的网名这么多〃 提交于 2019-11-26 15:52:18
问题 Are there functions for conversion between different coordinate systems? For example, Matlab has [rho,phi] = cart2pol(x,y) for conversion from cartesian to polar coordinates. Seems like it should be in numpy or scipy. 回答1: Using numpy, you can define the following: import numpy as np def cart2pol(x, y): rho = np.sqrt(x**2 + y**2) phi = np.arctan2(y, x) return(rho, phi) def pol2cart(rho, phi): x = rho * np.cos(phi) y = rho * np.sin(phi) return(x, y) 回答2: The existing answers can be simplified:

How do android screen coordinates work?

…衆ロ難τιáo~ 提交于 2019-11-26 15:38:24
I am working with Android Animation and I have found the Android coordinate system to be quite confusing so I am here to ask this question about how coordinates work in Android. I am following this image for moving one view to another but it seems it's not working: This image presents both orientation(Landscape/Portrait) To get MaxX and MaxY, read on. For Android device screen coordinates, below concept will work. Display mdisp = getWindowManager().getDefaultDisplay(); Point mdispSize = new Point(); mdisp.getSize(mdispSize); int maxX = mdispSize.x; int maxY = mdispSize.y; EDIT:- ** **for

Generating triangular/hexagonal coordinates (xyz)

假装没事ソ 提交于 2019-11-26 15:18:49
问题 I'm trying to come up with an iterative function that generates xyz coordinates for a hexagonal grid. With a starting hex position (say 0,0,0 for simplicity), I want to calculate the coordinates for each successive "ring" of hexagons, as illustrated here: So far, all I've managed to come up with is this (example in javascript): var radius = 3 var xyz = [0,0,0]; // for each ring for (var i = 0; i < radius; i++) { var tpRing = i*6; var tpVect = tpRing/3; // for each vector of ring for (var j =

Convert Lat/Longs to X/Y Co-ordinates

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-26 13:59:45
问题 I have the Lat/Long value of an small area in Melbourne; -37.803134,145.132377 and also a flat image of that,that I exported from openstreet map( Osmarender Image ). Image width : 1018 and Height:916 I would like to be able to convert, using C++, the Lat/Long to an X,Y coordinate where the point would reflect the location. I used various formula's that I found in web like one given below but nothing helps. var y = ((-1 * lat) + 90) * (MAP_HEIGHT / 180); var x = (lon + 180) * (MAP_WIDTH / 360)

Acceleration from device&#39;s coordinate system into absolute coordinate system

ぐ巨炮叔叔 提交于 2019-11-26 11:54:51
问题 From my Android device I can read an array of linear acceleration values (in the device\'s coordinate system) and an array of absolute orientation values (in Earth\'s coordinate system). What I need is to obtain the linear acceleration values in the latter coord. system. How can I convert them? EDIT after Ali\'s reply in comment: All right, so if I understand correctly, when I measure the linear acceleration, the position of the phone completely does not matter, because the readings are given

How to draw lines in Java

送分小仙女□ 提交于 2019-11-26 10:51:24
问题 I\'m wondering if there\'s a funciton in Java that can draw a line from the coordinates (x1, x2) to (y1, y2)? What I want is to do something like this: drawLine(x1, x2, x3, x4); And I want to be able to do it at any time in the code, making several lines appear at once. I have tried to do this: public void paint(Graphics g){ g.drawLine(0, 0, 100, 100); } But this gives me no control of when the function is used and I can\'t figure out how to call it several times. Hope you understand what I