Acceleration from device's coordinate system into absolute coordinate system

问题

From my Android device I can read an array of linear acceleration values (in the device\'s coordinate system) and an array of absolute orientation values (in Earth\'s coordinate system). What I need is to obtain the linear acceleration values in the latter coord. system.

How can I convert them?

EDIT after Ali\'s reply in comment:

All right, so if I understand correctly, when I measure the linear acceleration, the position of the phone completely does not matter, because the readings are given in Earth\'s coordinate system. right?

But I just did a test where I put the phone in different positions and got acceleration in different axes. There are 3 pairs of pictures - the first ones show how I put the device (sorry for my Paint \"master skill\") and the second ones show readings from data provided by the linear acc. sensor:

device put on left side

$\"first$ $\"first$

device lying on back

$\"second$ $\"second$

device standing

$\"enter$ $\"enter$

And now - why in the third case the acceleration occurs along the Z axis (not Y) since the device position doesn\'t matter?

回答1:

I finally managed to solve it! So to get acceleration vector in Earth's coordinate system you need to:

get rotation matrix (float[16] so it could be used later by android.opengl.Matrix class) from SensorManager.getRotationMatrix() (using SENSOR.TYPE_GRAVITY and SENSOR.TYPE_MAGNETIC_FIELD sensors values as parameters),
use android.opengl.Matrix.invertM() on the rotation matrix to invert it (not transpose!),
use Sensor.TYPE_LINEAR_ACCELERATION sensor to get linear acceleration vector (in device's coord. sys.),
use android.opengl.Matrix.multiplyMV() to multiply the rotation matrix by linear acceleration vector.

And there you have it! I hope I will save some precious time for others.

Thanks for Edward Falk and Ali for hints!!

回答2:

Based on @alex's answer, here is the code snippet:

private float[] gravityValues = null;
private float[] magneticValues = null;

 @Override
    public void onSensorChanged(SensorEvent event) {
        if ((gravityValues != null) && (magneticValues != null) 
            && (event.sensor.getType() == Sensor.TYPE_ACCELEROMETER)) {

            float[] deviceRelativeAcceleration = new float[4];
            deviceRelativeAcceleration[0] = event.values[0];
            deviceRelativeAcceleration[1] = event.values[1];
            deviceRelativeAcceleration[2] = event.values[2];
            deviceRelativeAcceleration[3] = 0;

            // Change the device relative acceleration values to earth relative values
            // X axis -> East
            // Y axis -> North Pole
            // Z axis -> Sky

            float[] R = new float[16], I = new float[16], earthAcc = new float[16];

            SensorManager.getRotationMatrix(R, I, gravityValues, magneticValues);

            float[] inv = new float[16];

            android.opengl.Matrix.invertM(inv, 0, R, 0);
            android.opengl.Matrix.multiplyMV(earthAcc, 0, inv, 0, deviceRelativeAcceleration, 0);
           Log.d("Acceleration", "Values: (" + earthAcc[0] + ", " + earthAcc[1] + ", " + earthAcc[2] + ")");                

        } else if (event.sensor.getType() == Sensor.TYPE_GRAVITY) {
            gravityValues = event.values;
        } else if (event.sensor.getType() == Sensor.TYPE_MAGNETIC_FIELD) {
            magneticValues = event.values;
        } 
   }

回答3:

According to the documentation you get the linear acceleration in the phone's coordinate system.

You can transform any vector from the phone's coordinate system to the Earth's coordinate system by multiplying it with the rotation matrix. You can get the rotation matrix from getRotationMatrix().

(Perhaps there already is a function doing this multiplication for you but I don't do Android programming and I am not familiar with its API.)

A nice tutorial on the rotation matrix is the Direction Cosine Matrix IMU: Theory manuscript. Good luck!

回答4:

OK, first of all, if you're trying to do actual inertial navigation on Android, you've got your work cut out for you. The cheap little sensor used in smart phones are just not precise enough. Although, there has been some interesting work done on intertial navigation over small distances, such as inside a building. There are probably papers on the subject you can dig up. Google "Motion Interface Developers Conference" and you might find something useful -- that's a conference that Invensense put on a couple months ago.

Second, no, linear acceleration is in device coordinates, not world coordinates. You'll have to convert yourself, which means knowing the device's 3-d orientation.

What you want to do is use a version of Android that supports the virtual sensors TYPE_GRAVITY and TYPE_LINEAR_ACCELERATION. You'll need a device with gyros to get reasonably accurate and precise readings.

Internally, the system combines gyros, accelerometers, and magnetometers in order to come up with true values for the device orientation. This effectively splits the accelerometer device into its gravity and acceleration components.

So what you want to do is to set up sensor listeners for TYPE_GRAVITY, TYPE_LINEAR_ACCELERATION, and TYPE_MAGNETOMETER. Use the gravity and magnetometer data as inputs to SensorManager. getRotationMatrix() in order to get the rotation matrix that will transform world coordinates into device coordinates or vice versa. In this case, you'll want the "versa" part. That is, convert the linear acceleration input to world coordinates by multiplying them by the transpose of the orientation matrix.

来源：https://stackoverflow.com/questions/11578636/acceleration-from-devices-coordinate-system-into-absolute-coordinate-system

标签

android