compression

问题 I'm trying to enable http response compression on Spring boot web application. It works for some user-agents, and for some reason doesn't for others (specific cases below). My basic question is: Why http response compression (gzip) in Spring Boot works only for some User-Agent headers and where it is configured. Spring boot reference doesn't say anything about it. I prepared simple web application with enabled compression: sample spring-boot-compression app There are integration tests that

问题 I can do basic regex alright, but this is slightly different, namely I don't know what the pattern is going to be. For example, I have a list of similar strings: lst = ['asometxt0moretxt', 'bsometxt1moretxt', 'aasometxt10moretxt', 'zzsometxt999moretxt'] In this case the common pattern is two segments of common text: 'sometxt' and 'moretxt' , starting and separated by something else that is variable in length. The common string and variable string can of course occur at any order and at any

问题 I have an int and float array each of length 220 million (fixed). Now, I want to store/upload those arrays to/from memory and disk. Currently, I am using Java NIO's FileChannel and MappedByteBuffer to solve this. It works fine, but it takes near about 5 seconds (Wall Clock Time) for storing/uploading array to/from memory to disk. Now, I want to make it faster. Here, I should mention most of those array elements are 0 ( nearly 52 %). like: int arr1 [] = { 0 , 0 , 6 , 7 , 1, 0 , 0 ...} Can

问题 Okay so I have some data streams compressed by python's (2.6) zlib.compress() function. When I try to decompress them, some of them won't decompress (zlib error -5, which seems to be a "buffer error", no idea what to make of that). At first, I thought I was done, but I realized that all the ones I couldn't decompress started with 0x78DA (the working ones were 0x789C), and I looked around and it seems to be a different kind of zlib compression -- the magic number changes depending on the

问题 I'm working on a solution to my other question which is reading the data in the 'zTXt' chunks of a PNG. I am as far as locating the chunks in the file, and reading the zTXt's keyword. I'm having trouble reading the compressed portion of zTXt. I've never worked with the DeflateStream object before, and am having some trouble with it. When reading, it appears to expect the length parameter to be in 'uncompressed' bytes. In my case however, I only know the length of the data in 'compressed'

问题 I have a Python script where I need to extract the contents of a ZIP file. However, the zip file is over 6GB in size. There is a lot of information about zlib and zipfile modules, however, I can't find a single approach that works in my case. I have the code: with zipfile.ZipFile(fname, "r") as z: try: log.info("Extracting %s " %fname) head, tail = os.path.split(fname) z.extractall(folder + "/" + tail) except zipfile.BadZipfile: log.error("Bad Zip file") except zipfile.LargeZipFile: log.error

问题 I have a Ruby program that zips a directory tree of XML files using the rubyzip gem. My problem is that the file is starting to be heavy and I would like to increase the compression level, since compression time is not an issue. I could not find in the rubyzip documentation a way to specify the compression level for the created ZIP file. Anyone know how to change this setting? Is there another Ruby library that allows to specify compression level? 回答1: Here is the code I created by looking at

问题 I'm using the zlib.NET library to try and inflate files that are compressed by zlib (on a Linux box, perhaps). Here's what I'm doing: zlib.ZInputStream zinput = new zlib.ZInputStream(File.Open(path, FileMode.Open, FileAccess.Read)); while (stopByte != (data = zinput.ReadByte())) { // check data here } zinput.Close(); The data bytes match the compressed data bytes, so I must be doing something wrong. 回答1: Other than failing to use a "using" statement to close the stream even in the face of an

问题 Problem: You have an N x N grid (1 <= N <= 10^9). Each square can either be traversed or is blocked. There are M (1 <= M <= 100) obstacles in the grid, each one shaped like a 1xK or Kx1 strip of grid squares. Each obstacle is specified by two endpoints (A_i, B_i) and (C_i, D_i), where A_i=C_i or B_i=D_i. You are also given a start square (X,Y). The question is: how many squares are reachable from the start square if you can go left, right, up, and down, and you cannot traverse obstacles? I

问题 I know there is system.io.compression.gzipstream but it accept a stream as arguments. I'm looking for a method that accept string eg. string compress(string stringtocompress,compressionlevel level); string decompress(string stringtodecompress); 回答1: you should try this: using System; using System.IO; using System.IO.Compression; using System.Text; ... public static string Compress(string s) { var bytes = Encoding.Unicode.GetBytes(s); using (var msi = new MemoryStream(bytes)) using (var mso =