comparison

问题 I am relatively new to C, I have to do it for school unfortunately and I am having issues with it at the easiest exercises. Here I have to check if a number is in a certain interval, for example between 4 and 6. I made it like this. #include <stdio.h> int main(){ int i; printf("Value to check Interval \n"); scanf("%s", i); if (i>4 && i<6){ printf("%s Value is in first interval\n", i); } } The scanf to enter the number and check if it is in the interval. But even if I enter a number that is

问题 I tried using cmp(list1, list2) to learn it's no longer supported in Python 3.3. I've tried many other complex approaches, but none have worked. I have two lists of which both contain just words and I want it to check to see how many words feature in both and return the number for how many. 回答1: You can find the length of the set intersection using & like this: len(set(list1) & set(list2)) Example: >>>len(set(['cat','dog','pup']) & set(['rat','cat','wolf'])) 1 >>>set(['cat','dog','pup']) &

问题 I tried using cmp(list1, list2) to learn it's no longer supported in Python 3.3. I've tried many other complex approaches, but none have worked. I have two lists of which both contain just words and I want it to check to see how many words feature in both and return the number for how many. 回答1: You can find the length of the set intersection using & like this: len(set(list1) & set(list2)) Example: >>>len(set(['cat','dog','pup']) & set(['rat','cat','wolf'])) 1 >>>set(['cat','dog','pup']) &

问题 I want to compare three strings: "a text string" //target string "a kind of similar text string" "the cow jumps over the moon" And set a percentage parameter that returns the results that are x% similar to the target. $results = compare($array,$target,80) $results // Returns an array with str 1,2, because they are at least 80 similar to the target. Also, is a similar function possible in JavaScript or jQuery? 回答1: In PHP, there is the function similar_text. As for JavaScript, there's the PHP

问题 What I want to do is check an array of strings against my search string and get the corresponding key so I can store it. Is there a magical way of doing this with Perl, or am I doomed to using a loop? If so, what is the most efficient way to do this? I'm relatively new to Perl (I've only written 2 other scripts), so I don't know a lot of the magic yet, just that Perl is magic =D Reference Array: (1 = 'Canon', 2 = 'HP', 3 = 'Sony') Search String: Sony's Cyber-shot DSC-S600 End Result: 3 回答1:

问题 Edit: This question covers two topics: The efficiency of using in double in place of float Float precision following rounding Is there any reason why I should not always use Java double instead of float? I ask this question because this test code when using floats is failing and not clear why since the only difference is the use of float instead of double. public class BigDecimalTest { @Test public void testDeltaUsingDouble() { //test passes BigDecimal left = new BigDecimal("0.99").setScale(2

问题 I have a class, user , that has an attribute metadata . metadata is a list of objects, each with different classes, for example: user.metatada = [Employee(), Student(), OtherClass()] In an update script, I need to check, if a certain type exists in a list, like so: if type(Employee()) in user.metadata: replace user.metadata[indexOfThatEmployee] with new Employee() else: user.metadata.append(new Employee()) is there anyway to easily to check if a certain type exists in a list? 回答1: Got it.

问题 I'm trying to check if a list is a subset of another in java . I used the for loop to check the elements and i have a variable called same that is incremented each time the elements are the same . The problem is that the list returns true only if the elements are in identical positions For example : (0,1) (0,1,2,3 ) true (1,0) (0,1,2,3) false I have written the code below : public Boolean contains(ItemsList ilist) { int same = 0; if (empty()) { return false; } else { ItemNode a = this.first;

问题 According to the Ruby Set class's documentation, "== Returns true if two sets are equal. The equality of each couple of elements is defined according to Object#eql?. The essence of this can be demonstrated using Date objects, where sets containing different Date objects but with the same date compare to equal: require 'set' d1 = Date.today # => Thu, 30 Sep 2010 puts d1.object_id # => 2211539680 d2 = Date.today + 1 # => Fri, 01 Oct 2010 puts d2.object_id # => 2211522320 set1 = Set.new([d1, d2]

问题 I'm looking either for routine or way to look for error tolerating string comparison. Let's say, we have test string Čakánka - yes, it contains CE characters. Now, I want to accept any of following strings as OK : cakanka cákanká ČaKaNKA CAKANKA CAAKNKA CKAANKA cakakNa The problem is, that I often switch letters in word, and I want to minimize user's frustration with not being able (i.e. you're in rush) to write one word right. So, I know how to make ci comparison (just make it lowercase :]),