comparison

问题 How to check if two series of dates overlap and determine the first date that it occurs? Imagine that I've created two events in Google Calendar. One of them in Date1 and repeating every X days; the other in Date2 and repeating every Y days. What would be the best algorithm to determine if the two series will overlap someday, and find the first date that it would happen? Example 1: Date1 = Feb-15, 2016 X = 14 (repeat every 14 days) Date2 = Feb-22, 2016 Y = 21 (repeat every 21 days) Result:

问题 how to print the result in the separate dataframe after comparing it with two columns in different dataframes. consider two dataframes: df1 = pd.DataFrame({'col1':['audi','cars']}) df2 = pd.DataFrame({'col2':['audi','bike']}) print (df1) col1 0 audi 1 cars print (df2) col2 0 audi 1 bike now the result should be in a different dataframe. col1 col2 result 0 audi audi no change 1 cars bike changed 回答1: Use concat with numpy.where: df = pd.concat([df1, df2], axis=1) df['result'] = np.where(df[

问题 I have an Array and One String Value. I want to get the Hierarchy of the String into an Array. For example, I have a string value "Casuals". "Casuals" value is inside the "Shirts" object. "Shirts" value is inside the "Men" object. And "Men" value is inside the "Default Category" object. So, this is how the logic should be work. Here is my Sample Array: { "id": 2, "name": "Default Category", "children_data": [ { "id": 3, "name": "Men", "children_data": [ { "id": 11, "name": "T-Shirts",

问题 Edit: talking with a_horse_with_no_name I found that "IS" is a little bit different in SQLite allowing comparisons between NULL and values using "IS": stackoverflow.com/a/9102445/1470058. This clears up a lot of confusion for me. Thanks: The IS and IS NOT operators work like = and != except when one or both of the operands are NULL. In this case, if both operands are NULL, then the IS operator evaluates to 1 (true) and the IS NOT operator evaluates to 0 (false). If one operand is NULL and the

问题 I'm trying to make a function that will compare multiple variables to an integer and output a string of three letters. I was wondering if there was a way to translate this into Python. So say: x = 0 y = 1 z = 3 mylist = [] if x or y or z == 0 : mylist.append("c") if x or y or z == 1 : mylist.append("d") if x or y or z == 2 : mylist.append("e") if x or y or z == 3 : mylist.append("f") which would return a list of ["c", "d", "f"] Is something like this possible? 回答1: You misunderstand how

问题 I have several rows of Excel cells which contain a string of words, all separated by commas. I want to compare each cell with another cell to check if any of the words match/are duplicates. For example: cell A1: dog, cat, rabbit, mouse, lion, bear, tiger cell A2: sausage, pickle, dog, cat, elephant, bread result: dog, cat The result could also be a number (e.g. 2) if that is easier. Many thanks! 回答1: I think you would be best served using VBA which you could then deploy as a User Defined

问题 This question already has answers here : How do chained comparisons in Python actually work? (1 answer) Python comparison operators chaining/grouping left to right? (1 answer) Closed 22 mins ago . Shouldn't it be parsed as (3 in [3]) == True since in and == have the same precedence? It's definitely not being parsed as 3 in ([3] == True) since that raises a TypeError . How else can it be parsed? p.s. I'm aware that PEP 8 says "Don't compare boolean values to True or False using == ." This is

问题 I'm trying to find a way to compare two images. Let me give you an example so you can better understand: my App will randomize a color (she will randomize a value from 0 to 255 for the R, then for the G and then for the B and the result is a completely random RGB color). Now the user will take a photo from the camera of the iPhone and the App will comprare the color with the image. Example: The App select the RGB = 205,133,63 wich is brown: the user will take a picture of a brown detail of a

问题 I know I ask too much, but maybe you can help with this problem too. a.txt contains words, b.txt contains strings. I would like to know how many string from b.txt ends with the words from a.txt Example: a.txt apple peach potato b.txt greenapple bigapple rottenapple pinkpeach xxlpotatoxxx Output 3 apple greenapple bigapple rottenapple 1 peach pinkpeach I would like to have a solution with grep, since it is way more faster than awk. Can you guys please help me? 回答1: Here is an awk solution awk

问题 I know I ask too much, but maybe you can help with this problem too. a.txt contains words, b.txt contains strings. I would like to know how many string from b.txt ends with the words from a.txt Example: a.txt apple peach potato b.txt greenapple bigapple rottenapple pinkpeach xxlpotatoxxx Output 3 apple greenapple bigapple rottenapple 1 peach pinkpeach I would like to have a solution with grep, since it is way more faster than awk. Can you guys please help me? 回答1: Here is an awk solution awk