comma

This program is for printing prime numbers till the input given and separating every prime number with a comma. void main(){ int N, counter=0, isPrime; int k, j; cout << "Enter maximum range: "; cin >> N; for (j=2; j<=N; j++){ isPrime = 0; k = 2; while (k<j){ if (j%k==0){ isPrime++; } k++; } if (isPrime==0){ if (k==N){ cout << j; } else{ cout << j << ","; } counter++; } } cout << endl; system("pause"); } It is only removing the last comma for prime number inputs, not for any other input. How can I fix this? Input: 23 Output: 2,3,5,7,11,13,17,19,23 Input: 8 Output: 2,3,5,7, Input: 9 Output: 2,3

I have read that comma operator is used to assign expression, and the right expression is supplied to lvalue. But why does this program assign left expression to lvalue when not using parenthesis.I am using turbo c compiler int b=2; int a; a=(b+2,b*5); // prints 10 as expected a=b+2,b*5; // prints 4 when not using parenthesis Also the following works int a =(b+2,b*5); And this generates error,I couldn't understand the reason. int a =b+2,b*5; // Error Because precedence of , operator is lower than of = one, this... a=b+2,b*5; ... will actually be evaluated as... a = b + 2; b * 5; With int i = b

I have been looking through some MFC code and i came across this expression. It was in OnInitDialog() function, didn't look like it's MFC specific. The variables had some name, value was 0. int volatile something, somethingElse; //this was global something, somethingElse = 0; //this was inside the function Does this make any sense in C++? I know how the comma operator works, though in a free form like here it should be separating expressions. Is a variable name also an expression? This code does compile, so how does this work? This is likely an error in the program. The statement a, b = c; Is

There is some kind of function for the printf function in which you can use %g, which will show the whole number 3 if the float is 3.00 and will show 3.01 if it's actually a float, is there any way you can do this through some code? There isn't really a simple answer Integral values do have exact representations in the float and double formats. So, if it's really already integral, you can use: f == floor(f) However, if your value is the result of a calculation which at one point involved any sort of non-zero fractional part, then you will need to be concerned that you may have something very

I need to write a variadic macro in C which must take zero or more arguments. In gcc, that can be achieved by adding "##" after the comma, e.g. ,##____VA_ARGS____ as answered in Variadic macros with zero arguments . However, the compiler in my build system (beyond my control) does not understand the ,## syntax and so does not swallow the comma. Is there a workaround I can use? Thanks! Yes, gcc swallowing the comma is non standard and you should not rely on that. With C99 conforming preprocessors you may achieve a similar effect by testing for a macro arguments that is the empty token. For the

I want to change on the yticklabel decimal separator from a decimal point to a comma, but leave the format of the offset text (1e-14), after using code from this code or that code . My questions: How can I change the point to a comma and save 1e-14? How can I change e to E in the offset text? I am using Python 3.5 tmdavison To change the decimal separator from a point to a comma, you can change the locale to somewhere where a comma is used. For example, here I set it to German: #Locale settings import locale # Set to German locale to get comma decimal separater locale.setlocale(locale.LC