clisp

Well, the flawed function is as follows: (defun make-matrix (n) (make-array (n n) :initial-element 0)) I want to use functions like (make-matrix 8) to replace the longer (make-array '(8 8) :initial-element 0) , but CLISP says there is a fault in (n n) , because n is not a defined function. How do I write this make-matrix function? You try to use (n n) , but that is Lisp syntax for calling a function named n with an argument n . You should invoke make-array like this: (make-array (list n n) :initial-element 0) 来源： https://stackoverflow.com/questions/19678906/how-to-modify-this-make-matrix

I was toying around with macros and clos, where I created an "object" macro to create instances (defmacro object (class &rest args) `(make-instance ',class ,@args)) Now doing this, I also ended up kind of wanting to do something similar for accessor functions created by clos. Example: (defclass person () ((name :accessor person-name :initarg :name))) then creating the instance (setf p1 (object person :name "tom")) now to get the name from the object obviously I would call person-name, however just as with the object macro, I wanted to create a "gets" macro to do this. So ideally: (gets person

I am currently reading ANSI Common Lisp by Paul Graham, and I have a question about writing lambda expressions. Do we need to prefix a lambda expression with #' ?. If I write something like this in REPL, it will work fine > ((lambda (x) (+ x 1)) 1) 2 so will this > (mapcar (lambda (x) (+ x x)) '(1 2 3 4)) (2 4 6 8) I understand that #' denotes a function. So my question is, is it some sort of convention or recommended practice? Can anything go wrong if I don't prefix lambdas with #' , is it implementation dependent? The LAMBDA expression (lambda ...) is considered to be a lambda expression

I found a Similar question . But I don't quite understand that explanation. So I'm trying to run clisp with the following example: [1]> (defvar a 5) A [2]> (+ a 1) 6 [3]> (defparameter b 5) B [4]> (+ b 1) 6 [5]> (setf c 5) 5 [6]> (+ c 1) 6 [7]> (setq d 5) 5 [8]> (+ d 1) 6 [9]> (let ((a 500)) (+ a 1)) 501 [10]> (let ((b 500)) (+ b 1)) 501 [11]> (let ((c 500)) (+ c 1)) 501 [12]> (let ((d 500)) (+ d 1)) 501 [13]> What I found is totally the same. I can't figure out what's different with them? Michał Kwiatkowski DEFPARAMETER always assigns a value. So: [1]> (defparameter a 1) A [2]> (defparameter

I've just started learning Lisp and I can't figure out how to compile and link lisp code to an executable. I'm using clisp and clisp -c produces two files: .fas .lib What do I do next to get an executable? thekidder I was actually trying to do this today, and I found typing this into the CLisp REPL worked: (EXT:SAVEINITMEM "executable.exe" :QUIET t :INIT-FUNCTION 'main :EXECUTABLE t :NORC t) where main is the name of the function you want to call when the program launches, :QUIET t suppresses the startup banner, and :EXECUTABLE t makes a native executable. It can also be useful to call (EXT