byte

问题 I have array with bits: var bits: [Bit] and how could I convert it to bytes array: var bytes: [UInt8] For example I have 280 bits and I should have 35 UInt8 in bytes array. I can think of solution where I take 8bits and check if first is true, if second is true and so and sum the results and have value. This I would do for every 8bits in my bits array. But I think this would be bad solution (it would work but with unnecessary calculations). I think there could be faster solution with some

问题 I have array with bits: var bits: [Bit] and how could I convert it to bytes array: var bytes: [UInt8] For example I have 280 bits and I should have 35 UInt8 in bytes array. I can think of solution where I take 8bits and check if first is true, if second is true and so and sum the results and have value. This I would do for every 8bits in my bits array. But I think this would be bad solution (it would work but with unnecessary calculations). I think there could be faster solution with some

问题 I have this code: Int32 i1 = 14000000; byte[] b = BitConverter.GetBytes(i1); string s = System.Text.Encoding.UTF8.GetString(b); byte[] b2 = System.Text.Encoding.UTF8.GetBytes(s); Int32 i2 = BitConverter.ToInt32(b2,0);; i2 is equal to -272777233. Why isn't it the input value? (14000000) ? EDIT: what I am trying to do is append it to another string which I'm then writing to file using WriteAllText 回答1: Because an Encoding class is not going to just work for anything. If a "character" (possibly

问题 I want to understand how to convert signed number into unsigned. lets say I have this: byte number = 127; // '1111111' In order to make it unsigned I have to choose "bigger" data type 'short' and apply AND operator with value 0x00ff. short number2; number2 = number & 0x00ff; Why does it make the number unsigned? 回答1: Java doesn't actually have unsigned primitives. The value 127 is actually represented by '01111111' the first bit being the sign (0 is positive). An unsigned byte would be able

问题 If I have to handle values to be stored in bytes like 0x118, how do I split the LSB and MSB? I was trying the following way... I don't think that it's the right way: value = 0x118; Storing in bytes... result[5] = (byte) value; result[6] = (byte)(value << 8); ... What is the correct way? 回答1: This will do it: result[5] = (byte) (value & 0xFF); // Least significant "byte" result[6] = (byte) ((value & 0xFF00) >> 8); // Most significant "byte" I usually use bit masks - maybe they're not needed.

问题 I've built a Python Steganographer and am trying to add a GUI to it. After my previous question regarding reading all kinds of files in Python. Since, the steganographer can only encode bytes in image. I want to add support to directly encode a file of any extension and encoding in it. For this, I am reading the file in binary and trying to encode it. It works fine for files which basically contains plain-text UTF-8 because it can easily encode .txt and .py files. My updated code is: from PIL

问题 Basically I am inserting an image using the listviews inserting event, trying to resize an image from the fileupload control, and then save it in a SQL database using LINQ. I found some code to create a new bitmap of the content in the fileupload control, but this was to store it in a file on the server, from this source, but I need to save the bitmap back into the SQL database, which I think I need to convert back into a byte[] format. So how do I convert the bitmap to a byte[] format? If I

问题 I use C#, wpf. I have an image, it is stored in the form of: byte[ ] public interface IFile { int Id { get; set; } byte[] FileData { get; set; } string FileName { get; set; } int? FileSize { get; set; } string FileExtension { get; set; } } How can I display my image (FileData byte[ ] ) on the form? <GroupBox BorderThickness="1"> <Image Source="..."/> </GroupBox> I have to write in Source="..." , if I create a temporary file from a byte[ ]? 回答1: Provided that you have a view model class that

问题 I have this issue and I can't figure out how to solve it. I have this string: data = '\xc4\xb7\x86\x17\xcd' When I tried to encode it: data.encode() I get this result: b'\xc3\x84\xc2\xb7\xc2\x86\x17\xc3\x8d' I only want: b'\xc4\xb7\x86\x17\xcd' Anyone knows the reason and how to fix this. The string is already stored in a variable, so I can't add the literal b in front of it. 回答1: You cannot convert a string into bytes or bytes into string without taking an encoding into account. The whole

问题 Essentially I made a request to a website and got a byte response back: b'[{"geonameId:"703448"}..........'. I'm confused because although it is of type byte, it is very human readable and appears like a list of json. I do know that the response is encoded in latin1 from running r.encoding which returned ISO-859-1 and I have tried to decode it, but it just returns an empty string. Here's what I have so far: r = response.content string = r.decode("ISO-8859-1") print (string) and this is where