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问题 I'm wondering if it's possible to count and print the number of bytes downloaded while the file is being downloaded. out, err := os.Create("file.txt") defer out.Close() if err != nil { fmt.Println(fmt.Sprint(err) ) panic(err) } resp, err := http.Get("http://example.com/zip") defer resp.Body.Close() if err != nil { fmt.Println(fmt.Sprint(err) ) panic(err) } n, er := io.Copy(out, resp.Body) if er != nil { fmt.Println(fmt.Sprint(err) ) } fmt.Println(n, "bytes ") 回答1: If I understand you

问题 I am reading a file with BinaryReader. There are data I want to pull at the address 0x37E but it is int24. So even I read 3 bytes, I can't convert it to int24. Do you have any suggestion? I'm using C# and am working on STFS package stuff. 回答1: In order to transform a byte array to an int24, you need to know the endianness of the data. This means: the information if 11 22 33 is supposed to mean 0x112233 or 0x332211 . Depending on this endianness, you can convert the data such as int24 result

问题 I want to unpack a binary string into into an array by a weird sequence of 8-8-8-7 bits. I could easily do something like this, for a normal 8-8-8-8 sequence: $b=unpack('C*',$data); for ($i=0,$count=sizeof($b); $i < $count; $i+=4) { $out[]=array($b[$i+1],$b[$i+2],$b[$i+3],$b[$i+4]); } That would give me a 2D array of bytes, grouped by 4. But as the fourth being 7 bits, I just can't think of anything appropriate. Have you got some ideas? 回答1: Not sure if I completely understand, but if you

问题 I wanna read first 188 bytes from a binary file, and check whether the first character is 0x47 . Code below: import os fp=open("try.ts","rb") for i in range(100): buf=fp.read(188) if buf[0]=="\x47": print "OK" fp.close() But it gives: if buf[0]=="\x47": IndexError: string index out of range My questions are: What's the type of a return value in read() function? How can I get the first character in a string or array? 回答1: if buf[0]=="\x47": IndexError: string index out of range That means your

问题 as the title says, how do I do it? Its easy to convert from string -> byte -> string binary, But how do I convert back? Below is a example. The output is : 'f' to binary: 01100110 294984 I read somewhere that I could use the Integer.parseInt but clearly that is not the case :( Or am I doing something wrong? Thanks, :) public class main{ public static void main(String[] args) { String s = "f"; byte[] bytes = s.getBytes(); StringBuilder binary = new StringBuilder(); for (byte b : bytes) { int

问题 I have been trying to write a function that takes two pointers (an input and an output) and writes the bytes from the input into the output in reverse order. So far I have not been able to make it work correctly. procedure ReverseBytes(Source, Dest: Pointer; Size: Integer); var Index: Integer; begin Move(Pointer(LongInt(Source) + Index)^, Pointer(LongInt(Dest) + (Size - Index))^ , 1); end; Can anyone please suggest a better way of doing this. Thanks. 回答1: procedure ReverseBytes(Source, Dest:

问题 Why doesn't send() in winsock guarantee delivery of the all bytes you request? This is TCP and it's blocking sockets. Similarly, this happens when non-blocking. How can you guarantee that you send everything? I've noticed recv() does the same. 回答1: If it didn't send everything, just call send again on the rest. If blocking, you can do it immediately. If non-blocking, you can either wait or use a socket discovery method (like select or I/O completion ports). The same goes for recv . If you

问题 I have a method which takes a hex value and assign it as a plaintext but type of byte like that byte plainText = 0xd7; I want to take this value from textbox ,for exmaple the user will type d7 to textbox and ı will assign it like byte plaintText = 0xd7 I could not achive that. 回答1: You can use the Convert.ToByte(String, Int32) method with the base set to 16 (hexadecimal): String text = "d7"; byte value = Convert.ToByte(text, 16); 回答2: Try this: var myByte = Byte.Parse("d7", NumberStyles

问题 I have a long array of bytes, with numbers from 0 to 255, and I know it's an image, so how can I save it like a file? I have tried a lot of things, but not success. The image is created but won't open because it's damaged. File .js function saveImage(filename, data){ //Data = [1,6,2,23,255,etc] var wstream = fs.createWriteStream(ARTWORK_PATH+filename); for (var i = 0; i < data.length; i++) { wstream.write(data[i].toString('base64')); } wstream.end(); } 回答1: Why use base64 encoding? If your

问题 I have a long array of bytes, with numbers from 0 to 255, and I know it's an image, so how can I save it like a file? I have tried a lot of things, but not success. The image is created but won't open because it's damaged. File .js function saveImage(filename, data){ //Data = [1,6,2,23,255,etc] var wstream = fs.createWriteStream(ARTWORK_PATH+filename); for (var i = 0; i < data.length; i++) { wstream.write(data[i].toString('base64')); } wstream.end(); } 回答1: Why use base64 encoding? If your