byte

问题 int port = 18000; DatagramSocket serverSocket = new DatagramSocket(port); byte[] receiveData = new byte[8]; System.out.println("Server Listing on Port: "+port); String x; while (true){ DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length); serverSocket.receive(receivePacket); ?? Double x = new Doulbe.parseBytes(recievedPacket) 回答1: You could use ByteBuffer Double x = ByteBuffer.wrap(receiveData).getDouble(); 回答2: Use java.nio.ByteBuffer Something like: private

问题 Is there a better way to convert a sequence of Bytes into an Seq[Boolean] where each element represents a bit from the Byte sequence? I'm currently doing this, but byte2Bools seems a little too heavy... object Main extends App { private def byte2Bools(b: Byte) = (0 to 7).foldLeft(ArrayBuffer[Boolean]())((bs, i) => bs += isBitSet(b, i)) private def isBitSet(byte: Byte, bit: Int) = ((byte >> bit) & 1) == 1 val bytes = List[Byte](1, 2, 3) val bools = bytes.flatMap(b => byte2Bools(b)) println

问题 When performing conversion from byte to double by mathematical operations I've got expected result. Performing the same mathematical operations to reverse the changes in value, results in correct value as long as I keep double type. But when at the end I converts double result back to byte value the conversion results is incorrect by 1. This is the case only for some byte values. Exact process: byte b = 82; Console.WriteLine(b); // initial byte value double d = (b / 100.0) + 2.00; Console

问题 When performing conversion from byte to double by mathematical operations I've got expected result. Performing the same mathematical operations to reverse the changes in value, results in correct value as long as I keep double type. But when at the end I converts double result back to byte value the conversion results is incorrect by 1. This is the case only for some byte values. Exact process: byte b = 82; Console.WriteLine(b); // initial byte value double d = (b / 100.0) + 2.00; Console

问题 In Python, I converted an image into bytes. Then, I pass the bytes to an Azure HTTP Trigger function app endpoint URL (Azure Portal) like this, just like usual when calling Azure cognitive services. image_path = r"C:\Users\User\Desktop\bicycle.jpg" image_data = open(image_path, "rb").read() print(len(image_data)) # print length to compare later url = "https://xxxx.azurewebsites.net/api/HTTPTrigger1........." headers = {'Content-Type': 'application/octet-stream'} response = requests.post(url,

问题 In Python, I converted an image into bytes. Then, I pass the bytes to an Azure HTTP Trigger function app endpoint URL (Azure Portal) like this, just like usual when calling Azure cognitive services. image_path = r"C:\Users\User\Desktop\bicycle.jpg" image_data = open(image_path, "rb").read() print(len(image_data)) # print length to compare later url = "https://xxxx.azurewebsites.net/api/HTTPTrigger1........." headers = {'Content-Type': 'application/octet-stream'} response = requests.post(url,

问题 Is there a way to construct a const integer from a literal byte expression, either using a byte string or a macro which constructs the integer? For example: const MY_ID: u16 = u16_code!(ID); const MY_WORD: u32 = u32_code!(WORD); const MY_LONG: u64 = u64_code!(LONGWORD); Or something similar, passing in b"ID" instead of ID ? * It should fail to compile when the wrong number of characters are passed too, something I couldn't figure out how to achieve when using bit-shifting on a literal byte

问题 I am currently trying to convert an integer variable to the value of a static uint8_t array in the Arduino IDE. I am using: #include <U8x8lib.h> And I do understand that uint8_t acts similarly to the byte type. Currently, the array has a set value: static uint8_t hello[] = "world"; From my perspective, "world" looks like a string, so I thought I would start with creating a string variable: String world = "world"; static uint8_t hello[] = world; This did not work and gave me the error:

问题 The content of a file is like following, and the file encoding is utf-8: cd232704-a46f-3d9d-97f6-67edb897d65f b'this Friday, Gerda Scheuers will be excited \xe2\x80\x94 but she\xe2\x80\x99s most excited about the merchandise the movie will bring.' Here is my code: with open(file, 'r') as f_in: for line in f_in: tokens = line.split('\t') print(tokens[1]) I want to get the right answer - "this Friday, Gerda Scheuers will be excited - but she's most excited about the merchandise the movie will

问题 I used to store the resources in the actual project, but I've switched to using a resource file instead. Originally I could ready the bytes for a file, but I'm finding it difficult doing this with a resource file. Any suggestions would be greatly appreciated. 回答1: public static byte[] ReadResource(string resourceName) { using (Stream s = Assembly.GetExecutingAssembly().GetManifestResourceStream(resourceName)) { byte[] buffer = new byte[1024]; using (MemoryStream ms = new MemoryStream()) {