byte

问题 I'm using the Zemanta API, which accepts up to 8 KB of text per call. I'm extracting the text to send to Zemanta from Web pages using JavaScript, so I'm looking for a function that will truncate my text at exactly 8 KB. Zemanta should do this truncation on its own (i.e., if you send it a larger string), but I need to shuttle this text around a bit before making the API call, so I want to keep the payload as small as possible. Is it safe to assume that 8 KB of text is 8,192 characters, and to

问题 Since SE 7 Java allows to specify values as binary literal. The documentation tells me 'byte' is a type that can hold 8 Bit of information, the values -128 to 127. Now i dont know why but i cannot define 8 bits but only 7 if i try to assign a binary literal to a byte in Java as follows: byte b = 0b000_0000; //solves to the value 0 byte b1 = 0b000_0001; //solves to the value 1 byte b3 = 0b000_0010; //solves to the value 2 byte b4 = 0b000_0011; //solves to the value 3 And so on till we get to

问题 How to convert byte[] to Byte[], and also Byte[] to byte[], in the case of not using any 3rd party library? Is there a way to do it fast just using the standard library? 回答1: Byte class is a wrapper for the primitive byte . This should do the work: byte[] bytes = new byte[10]; Byte[] byteObjects = new Byte[bytes.length]; int i=0; // Associating Byte array values with bytes. (byte[] to Byte[]) for(byte b: bytes) byteObjects[i++] = b; // Autoboxing. .... int j=0; // Unboxing Byte values. (Byte[

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . B8 00 B8 8E E8 B4 00 CD 16 65 88 00 EF F2 The program initially had 16 bytes, but I decided, to sacrifice 2 bytes in favor of unstable input position. Here is the previous version (0 0 position): 65 88 06 00 00

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . B8 00 B8 8E E8 B4 00 CD 16 65 88 00 EF F2 The program initially had 16 bytes, but I decided, to sacrifice 2 bytes in favor of unstable input position. Here is the previous version (0 0 position): 65 88 06 00 00

问题 Currently, we are building a robot with a raspberry pi and the AX-12 dynamixel Servo's. We found a python2 library we a currently porting to python3, we pinpointed the problem in a specific method that gives an error in python3. The Python 2 version actually works like a charm AX_GOAL_LENGTH = 5 AX_WRITE_DATA = 3 AX_GOAL_POSITION_L = 30 AX_START = 255 AX_REG_WRITE = 4 def move(self, id, position): self.direction(Ax12.RPI_DIRECTION_TX) Ax12.port.flushInput() p = [position&0xff, position>>8]

问题 In my android application i want to convert image ,taken from camera, to byte array and convert back to bitmap to view in a image view. I can do it easily through Bitmap.compress. But i want to do it without Bitmap.compress. The problem is that i am getting white lines (poor images every time(lines) ) Bitmap hello; //image coming from camera ByteBuffer buffer = ByteBuffer.allocate(hello.getByteCount()); hello.copyPixelsToBuffer(buffer); byte[] bytes1 = buffer.array(); byte [] Bits = new byte

问题 I have a binary file that is in the following format where each word is 4 bytes long: add arg1 arg2 arg3 // where in this example it would store the value of arg1+arg2 in arg3 I'm having trouble however figuring out a way to read the file in a way to where the first 4 bytes is an opcode, and the next 8 through 16 bytes represent the next 3 words per line. Below is my current code which I have not gotten working yet. #define buflen 9000 char buf1[buflen]; int main(int argc, char** argv){ int

问题 I use web service to get image. The service response contains image in base64Binary format. I try to decode response data with Base64.decode() (http://iharder.sourceforge.net/current/java/base64/). See my code below: byte[] data = Base64.decode(responseString); Bitmap bmp = BitmapFactory.decodeByteArray(data, 0, data.length); imageView.setImageBitmap(bmp); decodeByteArray always return null. I try to save data in .png file. I can open this file on my PC and in the Android File Manager

问题 I’m trying to convert a byte[] to a string and back using Encoding.Unicode. Sometimes Encoding.Unicode is able to convert the byte[] to a string and sometimes the output is != the input. What am I doing wrong? Thanks for your help. public static void Main(string[] args) { Random rnd = new Random(); while(true) { Int32 random = rnd.Next(10, 20); Byte[] inBytes = new Byte[random]; for(int i = 0; i < random; i++) inBytes[i] = (Byte)rnd.Next(0, 9); String inBytesString = Encoding.Unicode