boolean-logic

How do I test if a variable does not equal either of two values?

痞子三分冷 提交于 2019-11-27 11:07:14
I want to write an if/else statement that tests if the value of a text input does NOT equal either one of two different values. Like this (excuse my pseudo-English code): var test = $("#test").val(); if (test does not equal A or B){ do stuff; } else { do other stuff; } How do I write the condition for the if statement on line 2? Think of ! (negation operator) as "not", || (boolean-or operator) as "or" and && (boolean-and operator) as "and". See Operators and Operator Precedence . Thus: if(!(a || b)) { // means neither a nor b } However, using De Morgan's Law , it could be written as: if(!a &&

Element-wise logical OR in Pandas

﹥>﹥吖頭↗ 提交于 2019-11-27 08:48:13
I would like the element-wise logical OR operator. I know "or" itself is not what I am looking for. I am aware that AND corresponds to & and NOT, ~ . But what about OR? deinonychusaur The corresponding operator is | : df[(df < 3) | (df == 5)] would elementwise check if value is less than 3 or equal to 5. If you need a function to do this, we have np.logical_or . For two conditions, you can use df[np.logical_or(df<3, df==5)] Or, for multiple conditions use the logical_or.reduce , df[np.logical_or.reduce([df<3, df==5])] Since the conditions are specified as individual arguments, parentheses

Why TRUE == “TRUE” is TRUE in R?

回眸只為那壹抹淺笑 提交于 2019-11-27 07:44:28
Why TRUE == "TRUE" is TRUE in R? Is there any equivalent for === in R? Update: These are all returning FALSE : TRUE == "True" TRUE == "true" TRUE == "T" The only TRUE value is TRUE == "TRUE" . In case of checking with identical() everything works fine. Second Update: By === operator I meant the process of checking the Value and the Data Type of a variable . In this case I assumed that the == operator will only compare the Values of variables, not their Data Type as well. According to the help file ?`==` : If the two arguments are atomic vectors of different types, one is coerced to the type of

Dynamically evaluating simple boolean logic in Python

本小妞迷上赌 提交于 2019-11-27 05:44:25
问题 I've got some dynamically-generated boolean logic expressions, like: (A or B) and (C or D) A or (A and B) A empty - evaluates to True The placeholders get replaced with booleans. Should I, Convert this information to a Python expression like True or (True or False) and eval it? Create a binary tree where a node is either a bool or Conjunction / Disjunction object and recursively evaluate it? Convert it into nested S-expressions and use a Lisp parser? Something else? Suggestions welcome. 回答1:

Why does “one” < 2 equal FALSE in R?

馋奶兔 提交于 2019-11-27 05:24:47
I'm reading Hadley Wickham's Advanced R section on coercion, and I can't understand the result of this comparison: "one" < 2 # [1] FALSE I'm assuming that R coerces 2 to a character, but I don't understand why R returns FALSE instead of returning an error. This is especially puzzling to me since -1 < "one" # TRUE So my question is two-fold: first, why this answer, and second, is there a way of seeing how R converts the individual elements within a logical vector like these examples? jdharrison From help("<") : If the two arguments are atomic vectors of different types, one is coerced to the

False or None vs. None or False

允我心安 提交于 2019-11-27 05:18:05
问题 In [20]: print None or False -------> print(None or False) False In [21]: print False or None -------> print(False or None) None This behaviour confuses me. Could someone explain to me why is this happening like this? I expected them to both behave the same. 回答1: The expression x or y evaluates to x if x is true, or y if x is false. Note that "true" and "false" in the above sentence are talking about "truthiness", not the fixed values True and False . Something that is "true" makes an if

How do “and” and “or” work when combined in one statement?

落爺英雄遲暮 提交于 2019-11-27 03:30:22
问题 For some reason this function confused me: def protocol(port): return port == "443" and "https://" or "http://" Can somebody explain the order of what's happening behind the scenes to make this work the way it does. I understood it as this until I tried it: Either A) def protocol(port): if port == "443": if bool("https://"): return True elif bool("http://"): return True return False Or B) def protocol(port): if port == "443": return True + "https://" else: return True + "http://" Is this some

Boolean expression order of evaluation in Java?

北城余情 提交于 2019-11-27 02:04:33
问题 Suppose I have the following expression String myString = getStringFromSomeExternalSource(); if (myString != null && myString.trim().length() != 0) { ... } Eclipse warns me that myString might be null in the second phrase of the boolean expression. However, I know some that some compilers will exit the boolean expression entirely if the first condition fails. Is this true with Java? Or is the order of evaluation not guaranteed? 回答1: However, I know some that some compilers will exit the

Makefile ifeq logical AND

冷暖自知 提交于 2019-11-27 02:03:53
问题 I would like to check multiple conditions in an if loop of GNU make file. Here's an example: ifeq ($(TEST_FLAG),TRUE && ($(DEBUG_FLAG),FALSE)) true statement else false statement endif What's the right way to do it? 回答1: You can use ifeq with a concatenation of your values, eg. ifeq ($(TEST_FLAG)$(DEBUG_FLAG),TRUEFALSE) do something endif It's also possible to use the Conditional functions, which are more likely to be useful in a loop (as ifeq will probably not do what you expect in a loop,

Boolean checks in underscore templates

百般思念 提交于 2019-11-27 02:01:07
问题 I had to replace the default underscore teplating delimiters/Interpolate regex for compatibility with asp.net webforms.From the website i opted for mustache like syntax _.templateSettings = { interpolate : /\{\{(.+?)\}\}/g }; tried this _.template("{{if(loggedIn)Welcome {{name}}}}",{name:"James",completed:true}); but seems this is not the way( since a error occurred) to check boolean expression using a templating system. But from the docs seems it is possible as well as execute arbitrary