block

OSX Blocking JNLP Launch Java1.8U40 - Anyone Know Why?

由 十年热恋 提交于 2019-12-22 06:57:10
问题 We deploy our application as a JNLP launch file and/or as a webpage applet. I have a customer that updated his MAC OSX system to the latest Java Version 1.8_40. After upgrading the JNLP launch stopped working. It seems to start Java (flashes blue java logo) then stops. No Exception is thrown. I suspect yet another OSX security hurdle. We adjusted his OSX Security settings to trust our application. We adjusted his Java security to trust our site. We also adjusted the Safari preferences to

How is the value of a begin block determined?

由 半世苍凉 提交于 2019-12-22 06:33:43
问题 According to The Ruby Programming Language p.164. If a begin statement doesn't propagate an exception, then the value of the statement is the value of the last expression evaluated in the begin , rescue or else clauses. But I found this behavior consistent with the begin block together with else clause and ensure clause . Here is the example code: def fact (n) raise "bad argument" if n.to_i < 1 end value = begin fact (1) rescue RuntimeError => e p e.message else p "I am in the else statement"

Blocks and retain cycles

由 馋奶兔 提交于 2019-12-22 05:13:53
问题 One minor question: why is Xcode complaining that listing 1 would lead to a retain cycle, while in listing 2 it does not? In both cases _clients is an int instance variable. In listing 2 it is assigned 0 in the init method. Background info: I would like to execute the loop in the block, as long as at least one client is requesting updates from the iPhone accelerometer, which I am publishing to a redis channel. If there are no more clients left, the loop would quit and stop publishing

Synchronization on arguments of static methods

由 不打扰是莪最后的温柔 提交于 2019-12-21 21:51:20
问题 I have a question concerning the java synchronization with static methods. More precisely, I have a class with static methods that can be used concurrently by several threads. The principal static method of my class has one argument and calls the other auxiliary static methods one after the other passing them this argument. My question is the following: since the class can be used by multiple threads at a time, isn't there a risk that another thread replaces the argument by another one? I had

02HDFS架构

由 房东的猫 提交于 2019-12-21 15:45:47
https://www.cnblogs.com/zhoujingyu/p/5040957.html https://blog.csdn.net/firstchange/article/details/78567456 HDFS数据存储元（block） 　　- 文件被切分成固定大小的数据块 默认数据块大小为64MB（Hadoop1.x），128MB（Hadoop2.x）可以配置 若文件大小不到64MB，则单独存成一个block，大小是多少，占磁盘多少。 　　- 一个文件存储方式 按大小被切分成若干个block，存储到不同节点上 默认情况下每个block都有三个副本 　　- Block大小和副本数通过Clien端上传文件时设置，文件上传成功后副本数可以变更，Block Size不可变更 HDFS设计思想： NameNode（NN）： 　　- NameNode主要功能：接受客户端的读写服务 　　- NameNode保存metadata信息，包括： 整个文件系统的目录信息 文件owership（所有者）和permissions（权限） 文件包含哪些block 文件包含的Block保存在哪个DataNode（由DataNode启动时上报） 　　- NameNode的metadata信息在启动后会加载到内存： metadata存储到磁盘文件名为“fsimage” （持久化，文件的权限信息

posix threads block signal and unblock

由 牧云@^-^@ 提交于 2019-12-21 12:40:04
问题 Is there a way to block certain signals and unblock other signals in the same set? I just dont seem to get my head around it! An example sigset_t set; sigemptyset(&set); sigaddset(&set, SIGUSR1); // Block signal SIGUSR1 in this thread pthread_sigmask(SIG_BLOCK, &set, NULL); sigaddset(&set, SIGALRM); // Listen to signal SIGUSR2 pthread_sigmask(SIG_UNBLOCK, &set, NULL); pthread_t printer_thread1, printer_thread2; pthread_create(&printer_thread1, NULL, print, (void *)&f1); pthread_create(

How to handle looping code with blocks? [closed]

由 早过忘川 提交于 2019-12-21 03:12:09
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 6 years ago . I have some code which requires the use of blocks. The block fetches a number of data items from a web service, and then possibly needs to fetch more, and then more again after that, then returns all of the data items once it has all required. I'm unsure how to put this into code.

ruby中Block, Proc 和 Lambda 的区别

由 谁都会走 提交于 2019-12-20 19:42:58
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> Block 与Proc的区别： Block是代码块，Proc是对象； 参数列表中最多只能有一个Block， 但是可以有多个Proc或Lambda; Block可以看成是Proc的一个类实例. Proc 与Lambda 区别： Proc和Lambda都是Proc对象； Lambda检查参数个数，当传递的参数超过一个时，会报错，而Proc不检查，当传递参数多于一个时， 只传递第一个参数， 忽略掉其他参数; Proc和Lambda中return关键字的行为是不同的. # Block Examples [ 1 , 2 , 3 ]. each { | x | puts x * 2 } # block is in between the curly braces [ 1 , 2 , 3 ]. each do | x | puts x * 2 # block is everything between the do and end end # Proc Examples p = Proc . new { | x | puts x * 2 } [ 1 , 2 , 3 ]. each ( & p ) # The '&' tells ruby to turn the proc into a block proc = Proc .

Ruby Block/Procedure/Lambdas/Method/Symbol

由 China☆狼群 提交于 2019-12-20 19:42:09
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 参考文档 Understanding Ruby Blocks, Procs and Lambdas The Difference Between Ruby Symbols and Strings Block 和 Procedure 这个在上一篇文章中已经记录，Block其实就是Procedure，只是没有变量指向它不可复用。 def show_type(&obj) puts obj.class end show_type {} # => Proc Lambdas Ruby通过以下方式支持lambda方式： def lambda_call(lam) lam.call end lambda_call lambda{puts "lambda"} Method Ruby 还可以直接调用method对象： def generic_return(block) block.call end def method_demo puts "method" end generic_return method(:method_demo) # =》 method Block、Proc和Lambda、Method的区别 Lambda和Method的执行是方法栈的调用，而Block或Proc实际行为是类似于迁入代码中的一个代码块，如下：

理解Ruby的4种闭包：blocks, Procs, lambdas 和 Methods。

由 旧街凉风 提交于 2019-12-20 19:41:00
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> blocks, Procs, Methods, lambdas(也称闭包)是Ruby中最强大的一部分，用过你就会知道，同时也是最容易迷惑的。 这可能是因为Ruby处理闭包的方式有点怪。更甚的是，Ruby有4种处理闭包的方式, 第一次用，每种都不太顺手。 首先：blocks代码块 最常见、最简单、最富争议、最有Ruby风格的方式是blocks。写法如下： array = [1, 2, 3, 4] array.collect! do |n| n ** 2 end puts array.inspect # => [1, 4, 9, 16] do…end构成一个block。然后把这个block通过collect!传给一个数组。就可以使用block中的n来迭代数组中每个元素。 collect!是Ruby库里的方法，下面我们来写一个自己的类似方法iterate! class Array def iterate! self.each_with_index do |n, i| self[i] = yield(n) end end end array = [1, 2, 3, 4] array.iterate! do |n| n ** 2 end puts array.inspect # => [1, 4, 9, 16] 首先
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