bigint

如何选择合适的MySQL数据类型

浪尽此生 提交于 2019-11-28 07:14:51
MySQL数据类型选择 一 .选择原则 更小的通常更好 :一般情况下选择可以正确存储数据的最小数据类型。越小的数据类型通常更快,占用磁盘,内存和CPU缓存更小。 简单就好 :简单的数据类型的操作通常需要更少的CPU周期。例如:整型比字符操作代价要小得多,因为字符集和校对规则(排序规则)使字符比整型比较更加复杂。 尽量避免NULL :尽量制定列为NOT NULL,除非真的需要NULL类型的值。因为可能为NULL列使得索引,索引统计和值比较都更复杂。可为NULL的列会使用更多的存储空间,在MySQL里也需要特殊处理。 二.选择具体数据类型 在选择列的数据类型时需要先选定合适的大类型,如:数字,字符串,时间等。 整数类型 有两种类型的数字:整数和实数。如果需要存储整数,可以选择一下集中数据类型: 数据类型 长度/字节 范围 说明 TINYINT 1 -2^7—2^7-1 整数类型可选UNSIGND属性 SMALLINT 2 -2^15—2^15-1 表示不允许为负值 MEDIUMINT 3 -2^23—2^23-1 这大致可以使整数上限提高一倍 INT 4 -2^31—2^31-1 例如UNSIGNED可以使TINYINT BIGINT 8 -2^63—2^63-1 存储的范围是0—255 *实数类型 实数是带有小数部分的数字。然而它们不只是存储小数部分

Converting a big integer to decimal string

僤鯓⒐⒋嵵緔 提交于 2019-11-28 05:16:22
问题 At the risk of having this question voted as a duplicate, or even to have it closed, I had this question has come up. Background In "normal" data types such as int, long long, etc..., to convert from the binary numeric value to a decimal string, you would do the following (in pseudo code): Set length = 0 Set divisor to largest base10 value the data type will hold (Divisor). Loop Divide number in question by divisor. Place result in a string at position length. Increment the length by 1.

Base 36 to BigInt?

微笑、不失礼 提交于 2019-11-28 03:57:34
问题 Suppose I want to convert a base-36 encoded string to a BigInt , I can do this: BigInt(parseInt(x,36)) But what if my string exceeds what can safely fit in a Number? e.g. parseInt('zzzzzzzzzzzzz',36) Then I start losing precision. Are there any methods for parsing directly into a BigInt ? 回答1: You could convert the number to a bigint type. function convert(value, radix) { return [...value.toString()] .reduce((r, v) => r * BigInt(radix) + BigInt(parseInt(v, radix)), 0n); } console.log(convert(

What is the equivalent of bigint in C#?

时光怂恿深爱的人放手 提交于 2019-11-28 03:52:23
What I am supposed to use when handling a value in C#, which is bigint for an SQL Server database? Patrick Karcher That corresponds to the long (or Int64 ), a 64-bit integer. Although if the number from the database happens to be small enough, and you accidentally use an Int32, etc., you'll be fine. But the Int64 will definitely hold it. And the error you get if you use something smaller and the full size is needed? A stack overflow! Yay! ChaosPandion Int64 maps directly to BigInt . Source Robb Sadler I just had a script that returned the primary key of an insert and used a SELECT @@identity

How to format bigint field into a date in Postgresql?

自作多情 提交于 2019-11-27 17:05:16
问题 I have a table with a field of type bigint. This field store a timestamp. I want to date format the field like this : to_char( bigint_field,'DD/MM/YYYY HH24:MI:SS') I get the following error : ERROR: multiple decimal points État SQL :42601 回答1: TO_CHAR(TO_TIMESTAMP(bigint_field / 1000), 'DD/MM/YYYY HH24:MI:SS') 回答2: This depends on what the bigint value represents - offset of epoch time, or not. select to_timestamp(20120822193532::text, 'YYYYMMDDHH24MISS') returns "2012-08-22 19:35:32+00" 回答3

Fastest way to convert binary to decimal?

北战南征 提交于 2019-11-27 16:38:53
问题 I've got four unsigned 32-bit integers representing an unsigned 128-bit integer, in little endian order: typedef struct { unsigned int part[4]; } bigint_t; I'd like to convert this number into its decimal string representation and output it to a file. Right now, I'm using a bigint_divmod10 function to divide the number by 10, keeping track of the remainder. I call this function repeatedly, outputting the remainder as a digit, until the number is zero. It's pretty slow. Is this the fastest way

json_decode AND json_encode long integers without loosing data

旧时模样 提交于 2019-11-27 16:10:29
As noted in the PHP documentation, when json_decode ing a data structure containing long integers, they'll be converted to floats. The workaround is to use JSON_BIGINT_AS_STRING , which preserves them as strings instead. When json_encode ing such values, JSON_NUMERIC_CHECK will encode those numbers back into large integers: $json = '{"foo":283675428357628352}'; $obj = json_decode($json, false, JSON_BIGINT_AS_STRING); $json2 = json_encode($obj, JSON_NUMERIC_CHECK); var_dump($json === $json2); // true Using this method for a correct roundtrip of the data is prone to errors. If a property

node.js is there any proper way to parse JSON with large numbers? (long, bigint, int64)

ⅰ亾dé卋堺 提交于 2019-11-27 14:39:59
When I parse this little piece of JSON { "value" : 9223372036854775807 } that's what I get { hello: 9223372036854776000 } Is there any way to parse it properly? Not with built-in JSON.parse. You'll need to parse it manually and treat values as string (if you want to do arithmetics with them there is bignumber.js ) You can use Douglas Crockford JSON.js library as a base for your parser. EDIT: I created a package for you :) var JSONbig = require('json-bigint'); var json = '{ "value" : 9223372036854775807, "v2": 123 }'; console.log('Input:', json); console.log(''); console.log('node.js bult-in

Game of Connections

一个人想着一个人 提交于 2019-11-27 11:10:21
Game of Connections 这个题也是直接求 卡特兰数 ,不过数据有一点大,不能够直接求,因为杭电不能交 python 不然我就用 python 写了.... 对于这么大的数据,还不能写 python 就只能用 高精度 啦 代码: // Created by CAD on 2019/8/15. #include <bits/stdc++.h> #define mst(name, value) memset(name,value,sizeof(name)) using namespace std; using ll=long long; struct BigInt { const static int mod=1e4; const static int blo=4; int a[600], len; BigInt() { mst(a, 0), len=1; } BigInt(int v) //用int初始化 { mst(a, 0); len=0; do { a[len++]=v%mod; v/=mod; } while (v); } BigInt operator+(const BigInt &b) const //重载加法运算符 { BigInt res; res.len=max(len, b.len); for (int i=0; i<=res.len; ++i)

How are extremely large floating-point numbers represented in memory?

孤者浪人 提交于 2019-11-27 08:29:56
问题 How do arbitrary-precision libraries like GMP store extremely large floating-point numbers represented in memory? I would imagine that if for instance you wanted to compute Pi or Euler's constant to say, 2,000,000 digits that you would allocate a massive array of bytes for the digits to the right of the decimal place. Each byte would store 2 decimal place values and the array would be a member of a data structure with the number of digits and number of bytes used to store the value. Is this