axes

I think this is quite easy but I searched the internet and matplotlib users mailing list and not able to find an answer. ax2 is an inset axes within the "ax" axes in figure "fig", which I make by following here: http://matplotlib.sourceforge.net/examples/pylab_examples/axes_demo.html but now my problem is that I cannot fix the ax2 the exact position I want, it seems that draw() command change this: In [352]: ax2.set_position([0.125,0.63,0.25,0.25]) In [353]: ax2.get_position() Out[353]: Bbox(array([[ 0.125, 0.63 ], [ 0.375, 0.88 ]])) In [354]: draw() In [355]: ax2.get_position() Out[355]: Bbox

I'm looking at the custom projection example in the matplotlib gallery -- I'm trying to modify it to plot only the southern hemisphere. I have adjusted the necessary [-pi/2,pi/2] limits to [-pi/2,0]. Now I've been looking at: def _gen_axes_patch(self): """ Override this method to define the shape that is used for the background of the plot. It should be a subclass of Patch. In this case, it is a Circle (that may be warped by the axes transform into an ellipse). Any data and gridlines will be clipped to this shape. """ #return Circle((0.5, 0.5), 0.5) return Wedge((0.5,0.5), 0.5, 180, 360) def

看过前面的例子，会发现实现深度神经网络需要使用 tensorflow.nn 这个核心模块。我们通过源码来一探究竟。 1 # Copyright 2015 Google Inc. All Rights Reserved. 2 # 3 # Licensed under the Apache License, Version 2.0 (the "License"); 4 # you may not use this file except in compliance with the License. 5 # You may obtain a copy of the License at 6 # 7 # http://www.apache.org/licenses/LICENSE-2.0 8 # 9 # Unless required by applicable law or agreed to in writing, software 10 # distributed under the License is distributed on an "AS IS" BASIS, 11 # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 12 # See the License for the

I have an image: Here in the y-axis I would like to get 5x10^-5 4x10^-5 and so on instead of 0.00005 0.00004 . What I have tried so far is: fig = plt.figure() ax = fig.add_subplot(111) y_formatter = matplotlib.ticker.ScalarFormatter(useOffset=True) ax.yaxis.set_major_formatter(y_formatter) ax.plot(m_plot,densities1,'-ro',label='0.0<z<0.5') ax.plot(m_plot,densities2, '-bo',label='0.5<z<1.0') ax.legend(loc='best',scatterpoints=1) plt.legend() plt.show() This does not seem to work. The document page for tickers does not seem to provide a direct answer. You can use matplotlib.ticker.FuncFormatter

Say I have the following UL: <ul> <li>barry</li> <li>bob</li> <li>carl</li> <li>dave</li> <li>roger</li> <li>steve</li> </ul> I need to grab all the LIs between bob & roger. I can grab everything after bob with //ul/li[contains(.,"bob")]/following-sibling::li , and I can grab everything before roger with //ul/li[contains(.,"roger")]/preceding-sibling::li . The problem is when I try to combine the two, I end up getting extra results. For example, //ul/li[contains(.,"bob")]/following-sibling::li[contains(.,"roger")]/preceding-sibling::li will of course get everything before roger, instead of

I've got a GUI in MATLAB with a set of axes pre-placed. I'm using the location property of the legend to place it to the right hand side of the axes. However, by doing this the axes get re-scaled so that the axes+legend take up the original width of the axes. Is there any way to circumvent the re-size? Example: x=0:.1:10; y=sin(x); figure pos=get(gca,'position'); pos(3)=.5; %#re-size axes to leave room for legend set(gca,'position',pos) plot(x,y) So far I get: Place legend: legend('sin(x)','location','eastoutside') ...aaaaand... MATLAB squishes it all into the original axes space. Any way