angle

Math Calculation to retrieve angle between two points? [duplicate]

為{幸葍}努か 提交于 2019-11-30 02:44:41
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: How to calculate the angle between two points relative to the horizontal axis? I've been looking for this for ages and it's just really annoying me so I've decided to just ask... Provided I have two points (namely x1, y1, and x2, y2), I would like to calculate the angle between these two points, presuming that when y1 == y2 and x1 > x2 the angle is 180 degrees... I have the below code that I have been working

Get angle between point and origin

让人想犯罪 __ 提交于 2019-11-29 15:53:54
问题 This might have been answered before, sorry if it has. I basically need to get the angle from origin to point. So lets say Origin is (0, 0) and my target point is (3, 0) . 3 O'clock = 90 degrees 6 O'clock = 180 degrees 9 O'clock = 270 degrees 12 O'clock = 0 degrees Somehow, I gotta do some math magic, and find out that the angle is 90 degrees (Top is 0). The origin can vary, so I need a method with two parameters, Origin, and TargetPoint, which returns double Angle in Degrees. Yea, I realize

Angle Measurer in C#

我只是一个虾纸丫 提交于 2019-11-29 12:58:55
I want to make a tool that can measure angles between two user defined spots on a form. I have no code to do this at the moment, so any code would be appreciated. Thanks UPDATE It needs to be in Degrees and my points are 3 pictureboxes, each with different colours on each of the three points for the angle to be measured. UPDATE This is my new current code: namespace Angle_Measurer_Tool { public partial class Form1 : Form { public Form1() { InitializeComponent(); } int Dotter = 0; private void button1_Click(object sender, EventArgs e) { Dotter = 1; } public int Distance2D(int x1, int y1, int x2

calculating angle between two points on edge of circle Swift SpriteKit

大城市里の小女人 提交于 2019-11-29 12:27:20
问题 How would you calculate the degrees between two points on the edge of a circle in Swift. 回答1: Given points p1 , p2 on a circle with center center , you would compute the difference vectors first: let v1 = CGVector(dx: p1.x - center.x, dy: p1.y - center.y) let v2 = CGVector(dx: p2.x - center.x, dy: p2.y - center.y) Then let angle = atan2(v2.dy, v2.dx) - atan2(v1.dy, v1.dx) is the (directed) angle between those vectors in radians, and var deg = angle * CGFloat(180.0 / M_PI) the angle in degrees

Why do sin(45) and cos(45) give different results? [duplicate]

匆匆过客 提交于 2019-11-29 12:16:39
This question already has an answer here: Is floating point math broken? 30 answers This is something I wasn't expecting. I know these numbers are not 100% exact, but I wasn't expecting complementary angles giving different results of sin and cos : This following function returns 0.70710678118654746000000... sin(45 * PI / 180.0); while this follwing function returns 0.70710678118654757000000... cos(45 * PI / 180.0); so, it's: 0.707106781186547**46**000000... vs 0.707106781186547**57**000000... and not only those... sin(1 * PI / 180.0) also returns a slightly different number than cos(89 * PI /

How to calculate angle between two Geographical/GPS coordinates?

为君一笑 提交于 2019-11-29 07:05:12
I have two GPS Coordinates e.g. (Lat1, Long1) and (Lat2,Long2) Could anybody please help me find the angle between those two points. Values should be 0-360 degrees. npinti Taken from this previous SO post: float dy = lat2 - lat1; float dx = cosf(M_PI/180*lat1)*(long2 - long1); float angle = atan2f(dy, dx); I suppose you mean the bearing to and not the angle between the locations: If (lat1,long1) is stored in a Location object loc1 and (lat2,long2) is stored in loc2 you get the bearing from loc1 to loc2 like this: float bearing = loc1.bearingTo(loc2); The result is in degrees east of true north

Retrieve a positive or a negative angle from 3 points

眉间皱痕 提交于 2019-11-29 04:51:59
I am rotating points around a center point in 2D space. The points are the center point, the old mouse position, and the new mouse position. My rotation function works fine, and I can calculate the angle perfectly. But I want to calculate a negative angle if the user is moving their mouse in a direction which should be interpreted as counter-clockwise. For example, moving the mouse toward the right (positive x-axis) should rotate clockwise if you are above (less than) the y value of the center point, but it should rotate counter-clockwise if you are actually below (greater than) the y value of

Calculating angle between two points - java

岁酱吖の 提交于 2019-11-29 04:04:59
I need to calculate the angle in degrees between two points, with a fixed point that is connected with the given two points by a line. Here is an image that illustrates what I need: Here is what I have tried so far: public static float GetAngleOfLineBetweenTwoPoints(float x1, float x2, float y1, float y2) { float xDiff = x2 - x1; float yDiff = y2 - y1; return (float) (Math.atan2(yDiff, xDiff) * (180 / Math.PI)); } It's pointless to say that it doesn't provide the correct answer. You can have the following method that calculates the angle in radians using the Math.atan2 method: public static

How do I display an arrow positioned at a specific angle in MATLAB?

女生的网名这么多〃 提交于 2019-11-29 01:39:26
I am working in MATLAB and I'm stuck on a very simple problem: I've got an object defined by its position (x,y) and theta (an angle, in degrees). I would like to plot the point and add an arrow, starting from the point and pointing toward the direction defined by the angle. It actually doesn't even have to be an arrow, anything graphically showing the value of the angle will do! Here's a picture showing the kind of thing I'm trying to draw: removed dead ImageShack link The quiver() plotting function plots arrows like this. Take your theta value and convert it to (x,y) cartesian coordinates

From Cartesian Plot to Polar Histogram using Mathematica

主宰稳场 提交于 2019-11-28 23:55:40
Please Consider: dalist={{21, 22}, {26, 13}, {32, 17}, {31, 11}, {30, 9}, {25, 12}, {12, 16}, {18, 20}, {13, 23}, {19, 21}, {14, 16}, {14, 22}, {18,22}, {10, 22}, {17, 23}} ScreenCenter = {20, 15} FrameXYs = {{4.32, 3.23}, {35.68, 26.75}} Graphics[{EdgeForm[Thick], White, Rectangle @@ FrameXYs, Black, Point@dalist, Red, Disk[ScreenCenter, .5]}] What I would like to do is to compute, for each point, its angle in a coordinate system such as : Above is the Deisred output, those are frequency count of point given a particular "Angle Bin". Once I know how to compute the angle i should be able to do