Real world use cases of bitwise operators [closed]

匿名 (未验证) 提交于 2019-12-03 01:13:01

问题:

What are some real world use cases of the following bitwise operators?

  • AND
  • XOR
  • NOT
  • OR

回答1:

  • Bit fields (flags)
    They're the most efficient way of representing something whose state is defined by several "yes or no" properties. ACLs are a good example; if you have let's say 4 discrete permissions (read, write, execute, change policy), it's better to store this in 1 byte rather than waste 4. These can be mapped to enumeration types in many languages for added convenience.

  • Communication over ports/sockets
    Always involves checksums, parity, stop bits, flow control algorithms, and so on, which usually depend on the logic values of individual bytes as opposed to numeric values, since the medium may only be capable of transmitting one bit at a time.

  • Compression, Encryption
    Both of these are heavily dependent on bitwise algorithms. Look at the deflate algorithm for an example - everything is in bits, not bytes.

  • Finite State Machines
    I'm speaking primarily of the kind embedded in some piece of hardware, although they can be found in software too. These are combinatorial in nature - they might literally be getting "compiled" down to a bunch of logic gates, so they have to be expressed as AND, OR, NOT, etc.

  • Graphics There's hardly enough space here to get into every area where these operators are used in graphics programming. XOR (or ^) is particularly interesting here because applying the same input a second time will undo the first. Older GUIs used to rely on this for selection highlighting and other overlays, in order to eliminate the need for costly redraws. They're still useful in slow graphics protocols (i.e. remote desktop).

Those were just the first few examples I came up with - this is hardly an exhaustive list.



回答2:

Is it odd?

(value & 0x1) > 0 

Is it divisible by two (even)?

(value & 0x1) == 0 


回答3:

Low-level programming is a good example. You may, for instance, need to write a specific bit to a memory-mapped register to make some piece of hardware do what you want it to:

volatile uint32_t *register = (volatile uint32_t *)0x87000000; uint32_t          value; uint32_t          set_bit   = 0x00010000; uint32_t          clear_bit = 0x00001000;  value = *register;            // get current value from the register value = value & ~clear_bit;   // clear a bit value = value | set_bit;      // set a bit *register = value;            // write it back to the register 

Also, htonl() and htons() are implemented using the & and | operators (on machines whose endianness(Byte order) doesn't match network order):

#define htons(a) ((((a) & 0xff00) >> 8) | \                   (((a) & 0x00ff) << 8))  #define htonl(a) ((((a) & 0xff000000) >> 24) | \                   (((a) & 0x00ff0000) >>  8) | \                   (((a) & 0x0000ff00) <<  8) | \                   (((a) & 0x000000ff) << 24)) 


回答4:

I use them to get RGB(A) values from packed colorvalues, for instance.



回答5:

Here's some common idioms dealing with flags stored as individual bits.

enum CDRIndicators {   Local = 1 << 0,   External = 1 << 1,   CallerIDMissing = 1 << 2,   Chargeable = 1 << 3 };  unsigned int flags = 0; 

Set the Chargeable flag:

flags |= Chargeable; 

Clear CallerIDMissing flag:

flags &= ~CallerIDMissing; 

Test whether CallerIDMissing and Chargeable are set:

if((flags & (CallerIDMissing | Chargeable )) == (CallerIDMissing | Chargeable)) {  } 


回答6:

I've used bitwise operations in implementing a security model for a CMS. It had pages which could be accessed by users if they were in appropriate groups. A user could be in multiple groups, so we needed to check if there was an intersection between the users groups and the pages groups. So we assigned each group a unique power-of-2 identifier, e.g.:

Group A = 1 --> 00000001 Group B = 2 --> 00000010 Group C = 3 --> 00000100 

We OR these values together, and store the value (as a single int) with the page. E.g. if a page could be accessed by groups A & B, we store the value 3 (which in binary is 00000011) as the pages access control. In much the same way, we store a value of ORed group identifiers with a user to represent which groups they are in.

So to check if a given user can access a given page, you just need to AND the values together and check if the value is non-zero. This is very fast as this check is implemented in a single instruction, no looping, no database round-trips.



回答7:

When I have a bunch of boolean flags, I like to store them all in an int.

I get them out using bitwise-AND. For example:

int flags; if (flags & 0x10) {   // Turn this feature on. }  if (flags & 0x08) {   // Turn a second feature on. } 

etc.



回答8:

Encryption is all bitwise operations.



回答9:

I just used bitwise-XOR (^) about three minutes ago to calculate a checksum for serial communication with a PLC...



回答10:

You can use them as a quick and dirty way to hash data.

int a = 1230123; int b = 1234555; int c = 5865683; int hash = a ^ b ^ c; 


回答11:

& = AND:
Mask out specific bits.
You are defining the specific bits which should be displayed or not displayed. 0x0 & x will clear all bits in a byte while 0xFF will not change x. 0x0F will display the bits in the lower nibble.

Conversion:
To cast shorter variables into longer ones with bit identity it is necessary to adjust the bits because -1 in an int is 0xFFFFFFFF while -1 in a long is 0xFFFFFFFFFFFFFFFF. To preserve the identity you apply a mask after conversion.

|=OR
Set bits. The bits will be set indepently if they are already set. Many datastructures (bitfields) have flags like IS_HSET = 0, IS_VSET = 1 which can be indepently set. To set the flags, you apply IS_HSET | IS_VSET (In C and assembly this is very convenient to read)

^=XOR
Find bits which are the same or different.

~= NOT
Flip bits.

It can be shown that all possible local bit operations can be implemented by these operations. So if you like you can implement an ADD instruction solely by bit operations.

Some wonderful hacks:

http://www.ugcs.caltech.edu/~wnoise/base2.html
http://www.jjj.de/bitwizardry/bitwizardrypage.html



回答12:

Bitwise & is used to mask/extract a certain part of a byte.

1 Byte variable

 01110010 &00001111 Bitmask of 0x0F to find out the lower nibble  --------  00000010 

Specially the shift operator (<< >>) are often used for calculations.



回答13:

This is an example to read colours from a bitmap image in byte format

byte imagePixel = 0xCCDDEE; /* Image in RRGGBB format R=Red, G=Green, B=Blue */  //To only have red byte redColour = imagePixel & 0xFF0000; /*Bitmasking with AND operator */  //Now, we only want red colour redColour = (redColour >> 24) & 0xFF;  /* This now returns a red colour between 0x00 and 0xFF. 

I hope this tiny examples helps....



回答14:

Base64 encoding is an example. Base64 encoding is used to represent binary data as a printable characters for sending over email systems (and other purposes). Base64 encoding converts a series of 8 bit bytes into 6 bit character lookup indexes. Bit operations, shifting, and'ing, or'ing, not'ing are very useful for implementing the bit operations necessary for Base64 encoding and decoding.

This of course is only 1 of countless examples.



回答15:

I'm suprised no one picked the obvious answer for the Internet age. Calculating valid network addresses for a subnet.

http://www.topwebhosts.org/tools/netmask.php



回答16:

In the abstracted world of today's modern language, not too many. File IO is an easy one that comes to mind, though that's exercising bitwise operations on something already implemented and is not implementing something that uses bitwise operations. Still, as an easy example, this code demonstrates removing the read-only attribute on a file (so that it can be used with a new FileStream specifying FileMode.Create) in c#:

//Hidden files posses some extra attibutes that make the FileStream throw an exception //even with FileMode.Create (if exists -> overwrite) so delete it and don't worry about it! if(File.Exists(targetName)) {     FileAttributes attributes = File.GetAttributes(targetName);      if ((attributes & FileAttributes.ReadOnly) == FileAttributes.ReadOnly)         File.SetAttributes(targetName, attributes & (~FileAttributes.ReadOnly));      File.Delete(targetName); } 

As far as custom implementations, here's a recent example: I created a "message center" for sending secure messages from one installation of our distributed application to another. Basically, it's analogous to email, complete with Inbox, Outbox, Sent, etc, but it also has guaranteed delivery with read receipts, so there are additional subfolders beyond "inbox" and "sent." What this amounted to was a requirement for me to define generically what's "in the inbox" or what's "in the sent folder". Of the sent folder, I need to know what's read and what's unread. Of what's unread, I need to know what's received and what's not received. I use this information to build a dynamic where clause which filters a local datasource and displays the appropriate information.

Here's how the enum is put together:

    public enum MemoView :int     {         InboundMemos = 1,                   //     0000 0001         InboundMemosForMyOrders = 3,        //     0000 0011         SentMemosAll = 16,                  //     0001 0000         SentMemosNotReceived = 48,          //     0011         SentMemosReceivedNotRead = 80,      //     0101         SentMemosRead = 144,                //     1001         Outbox = 272,                       //0001 0001 0000         OutBoxErrors = 784                  //0011 0001 0000     } 

Do you see what this does? By anding (&) with the "Inbox" enum value, InboundMemos, I know that InboundMemosForMyOrders is in the inbox.

Here's a boiled down version of the method that builds and returns the filter that defines a view for the currently selected folder:

    private string GetFilterForView(MemoView view, DefaultableBoolean readOnly)     {         string filter = string.Empty;         if((view & MemoView.InboundMemos) == MemoView.InboundMemos)         {             filter = "";              if((view & MemoView.InboundMemosForMyOrders) == MemoView.InboundMemosForMyOrders)             {                 filter += "";             }         }         else if((view & MemoView.SentMemosAll) == MemoView.SentMemosAll)         {             //all sent items have originating system = to local             filter = "";              if((view & MemoView.Outbox) == MemoView.Outbox)             {                 ...             }             else             {                 //sent sub folders                 filter += "";                  if((view & MemoView.SentMemosNotReceived) == MemoView.SentMemosNotReceived)                 {                     if((view & MemoView.SentMemosReceivedNotRead) == MemoView.SentMemosReceivedNotRead)                     {                         filter += "";                     }                     else                         filter += "";                 }             }         }          return filter;     } 

Extremely simple, but a neat implementation at a level of abstraction that doesn't typically require bitwise operations.



回答17:

Nobody seems to have mentioned fixed point maths.

(Yeah, I'm old, ok?)



回答18:

it can also be handy in a sql relational model, let's say you have the following tables: BlogEntry, BlogCategory

traditonally you could create a n-n relationship between them using a BlogEntryCategory table or when there are not that much BlogCategory records you could use one value in BlogEntry to link to multiple BlogCategory records just like you would do with flagged enums, in most RDBMS there are also a very fast operators to select on that 'flagged' column...



回答19:

Is a number x a power of 2? (Useful for example in algorithms where a counter is incremented, and an action is to be taken only logarithmic number of times)

(x & (x - 1)) == 0 

Which is the highest bit of an integer x? (This for example can be used to find the minimum power of 2 that is larger than x)

x |= (x >>  1); x |= (x >>  2); x |= (x >>  4); x |= (x >>  8); x |= (x >> 16); return x - (x >>> 1); // ">>>" is unsigned right shift 

Which is the lowest 1 bit of an integer x? (Helps find number of times divisible by 2.)

x & -x 


回答20:

When you only want to change some bits of a microcontroller's Outputs, but the register to write to is a byte, you do something like this (pseudocode):

char newOut = OutRegister & 0b00011111 //clear 3 msb's newOut = newOut | 0b10100000 //write '101' to the 3 msb's OutRegister = newOut //Update Outputs 

Of course, many microcontrollers allow you to change each bit individually...



回答21:

Usually bitwise operations are faster than doing multiply/divide. So if you need to multiply a variable x by say 9, you will do x<<3 + x which would be a few cycles faster than x*9. If this code is inside an ISR, you will save on response time.

Similarly if you want to use an array as a circular queue, it'd be faster (and more elegant) to handle wrap around checks with bit wise operations. (your array size should be a power of 2). Eg: , you can use tail = ((tail & MASK) + 1) instead of tail = ((tail +1) < size) ? tail+1 : 0, if you want to insert/delete.

Also if you want a error flag to hold multiple error codes together, each bit can hold a separate value. You can AND it with each individual error code as a check. This is used in Unix error codes.

Also a n-bit bitmap can be a really cool and compact data structure. If you want to allocate a resource pool of size n, we can use a n-bits to represent the current status.



回答22:

I use them for multi select options, this way I only store one value instead of 10 or more



回答23:

I've seen them used in role based access control systems.



回答24:

There is a real world use in my question here -
Respond to only the first WM_KEYDOWN notification?

When consuming a WM_KEYDOWN message in the windows C api bit 30 specifies the previous key state. The value is 1 if the key is down before the message is sent, or it is zero if the key is up



回答25:

They are mostly used for bitwise operations (surprise). Here are a few real-world examples found in PHP codebase.

Character encoding:

if (s <= 0 && (c & ~MBFL_WCSPLANE_MASK) == MBFL_WCSPLANE_KOI8R) { 

Data structures:

ar_flags = other->ar_flags & ~SPL_ARRAY_INT_MASK; 

Database drivers:

dbh->transaction_flags &= ~(PDO_TRANS_ACCESS_MODE^PDO_TRANS_READONLY); 

Compiler implementation:

opline->extended_value = (opline->extended_value & ~ZEND_FETCH_CLASS_MASK) | ZEND_FETCH_CLASS_INTERFACE; 


回答26:

Whenever I first started C programming, I understood truth tables and all that, but it didn't all click with how to actually use it until I read this article http://www.gamedev.net/reference/articles/article1563.asp (which gives real life examples)



回答27:

I don't think this counts as bitwise, but ruby's Array defines set operations through the normal integer bitwise operators. So [1,2,4] & [1,2,3] # => [1,2]. Similarly for a ^ b #=> set difference and a | b #=> union.



回答28:

If you ever want to calculate your number mod(%) a certain power of 2, you can use yourNumber & 2^N-1, which in this case is the same as yourNumber % 2^N.

number % 16 = number & 15; number % 128 = number & 127; 

This is probably only useful being an alternative to modulus operation with a very big dividend that is 2^N... But even then its speed boost over the modulus operation is negligible in my test on .NET 2.0. I suspect modern compilers already perform optimizations like this. Anyone know more about this?



回答29:

Tower Of Hanoi linear solution uses bitwise operations to solve the problem.

public static void linear(char start, char temp, char end, int discs) {     int from,to;     for (int i = 1; i < (1 << discs); i++) {         from = (i & i-1) % 3;         to = ((i | i-1) + 1) % 3;         System.out.println(from+" => "+to);     } } 

The explanation for this solution can be found here



回答30:

Bitwise operators are useful for looping arrays which length is power of 2. As many people mentioned, bitwise operators are extremely useful and are used in Flags, Graphics, Networking, Encryption. Not only that, but they are extremely fast. My personal favorite use is to loop an array without conditionals. Suppose you have a zero-index based array(e.g. first element's index is 0) and you need to loop it indefinitely. By indefinitely I mean going from first element to last and returning to first. One way to implement this is:

int[] arr = new int[8]; int i = 0; while (true) {     print(arr[i]);     i = i + 1;     if (i >= arr.length)          i = 0; } 

This is the simplest approach, if you'd like to avoid if statement, you can use modulus approach like so:

int[] arr = new int[8]; int i = 0; while (true) {     print(arr[i]);     i = i + 1;     i = i % arr.length; } 

The down side of these two methods is that modulus operator is expensive, since it looks for a remainder after integer division. And the first method runs an if statement on each iteration. With bitwise operator however if length of your array is a power of 2, you can easily generate a sequence like 0 .. length - 1 by using & (bitwise and) operator like so i & length. So knowing this, the code from above becomes

int[] arr = new int[8]; int i = 0; while (true){     print(arr[i]);     i = i + 1;     i = i & (arr.length - 1); } 

Here is how it works. In binary format every number that is power of 2 subtracted by 1 is expressed only with ones. For example 3 in binary is 11, 7 is 111, 15 is 1111 and so on, you get the idea. Now, what happens if you & any number against a number consisting only of ones in binary? Let's say we do this:

num & 7; 

If num is smaller or equal to 7 then the result will be num because each bit &-ed with 1 is itself. If num is bigger than 7, during the & operation computer will consider 7's leading zeros which of course will stay as zeros after & operation only the trailing part will remain. Like in case of 9 & 7 in binary it will look like

1001 & 0111 

the result will be 0001 which is 1 in decimal and addresses second element in array.



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