RPC Client gives Can't encode arguments

问题:

I'm trying to write the simpliest client in RPC with this code:

#include <stdio.h> #include <stdlib.h> #include <rpc/rpc.h>  int main(int argc, char *argv[]){   int stat;   char out;     char in='f';    if(stat=callrpc(argv[1],0x20000001, 1, 1, (xdrproc_t)xdr_void, &in, (xdrproc_t)xdr_char, &out)!=0){       clnt_perrno(stat);       exit(1);   }    exit(0); }

It compiles, but when I try to run it, it gives me a "RPC: Can't encode arguments"

EDIT: Actually the server do not recieve any argument neither it send back anything, that's why I put a xdr_void added &in and &out to avoid segmentation fault error.

回答1:

You are missing some parentheses:

if (stat = callrpc(...) != 0)

is evaluated to

if (stat = (callrpc(...) != 0))

which always assigns 1 to stat in case of an error, which is RPC_CANTENCODEARGS. You need

if ((stat = callrpc(...)) != 0)

to get the real error code and message printed in

clnt_perrno(stat);

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