子查询经典案例

匿名 (未验证) 提交于 2019-12-03 00:30:01
# 1. 查询工资最低的员工信息: last_name, salary


#①查询最低的工资
SELECT MIN(salary)
FROM employees


#②查询last_name,salary,要求salary=①
SELECT last_name,salary
FROM employees
WHERE salary=(
SELECT MIN(salary)
FROM employees
);


# 2. 查询平均工资最低的部门信息


#方式一:
#①各部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
#②查询①结果上的最低平均工资
SELECT MIN(ag)
FROM (
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id
) ag_dep


#③查询哪个部门的平均工资=②


SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
SELECT MIN(ag)
FROM (
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id
) ag_dep


);


#④查询部门信息


SELECT d.*
FROM departments d
WHERE d.`department_id`=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
SELECT MIN(ag)
FROM (
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id
) ag_dep


)


);


#方式二:
#①各部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id


#②求出最低平均工资的部门编号
SELECT department_id
FROM employees
GROUP BY department_id

LIMIT 1;


#③查询部门信息
SELECT *
FROM departments
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id

LIMIT 1
);








# 3. 查询平均工资最低的部门信息和该部门的平均工资
#①各部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
#②求出最低平均工资的部门编号
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id

LIMIT 1;
#③查询部门信息
SELECT d.*,ag
FROM departments d
JOIN (
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id

LIMIT 1


) ag_dep
ON d.`department_id`=ag_dep.department_id;






# 4. 查询平均工资最高的 job 信息
#①查询最高的job的平均工资
SELECT AVG(salary),job_id
FROM employees
GROUP BY job_id
ORDER BY AVG(salary) DESC
LIMIT 1


#②查询job信息

FROM jobs
WHERE job_id=(
SELECT job_id
FROM employees
GROUP BY job_id
ORDER BY AVG(salary) DESC
LIMIT 1


);
# 5. 查询平均工资高于公司平均工资的部门有哪些?


#①查询平均工资
SELECT AVG(salary)
FROM employees


#②查询每个部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id


#③筛选②结果集,满足平均工资>①


SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)>(
SELECT AVG(salary)
FROM employees


);


# 6. 查询出公司中所有 manager 的详细信息.
#①查询所有manager的员工编号
SELECT DISTINCT manager_id
FROM employees


#②查询详细信息,满足employee_id=①
SELECT *
FROM employees
WHERE employee_id =ANY(
SELECT DISTINCT manager_id
FROM employees


);


# 7. 各个部门中 最高工资中最低的那个部门的 最低工资是多少


#①查询各部门的最高工资中最低的部门编号
SELECT department_id
FROM employees
GROUP BY department_id
ORDER BY MAX(salary)
LIMIT 1




#②查询①结果的那个部门的最低工资


SELECT MIN(salary) ,department_id
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
ORDER BY MAX(salary)
LIMIT 1




);
# 8. 查询平均工资最高的部门的 manager 的详细信息: last_name, department_id, email, salary
#①查询平均工资最高的部门编号


FROM






#②将employees和departments连接查询,筛选条件是①















文章来源: 子查询经典案例
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