【codevs1079】回家

匿名 (未验证) 提交于 2019-12-03 00:22:01

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//标程Dijkstra #include<iostream> #include<algorithm> #include<vector> using namespace std;  //T int n = 60, m, vis[1010];  //Graph struct Edge{     int v, w;     Edge(int v, int w):v(v),w(w){} }; vector<Edge>G[70];  //Dijkstra int dis[70], book[70], s = (int)'Z'-'A'; void Dijkstra(){     for(int i = 0; i < n; i++)dis[i] = 0xffffff;     for(int i = 0; i < G[s].size(); i++)//bugs数据可能有覆盖         dis[G[s][i].v] = min(dis[G[s][i].v],G[s][i].w);     dis[s] = 0;  book[s] = 1;     for(int i = 0; i < n; i++){         int v, w=0xffffff;         for(int j = 0; j < n; j++)             if(!book[j] && dis[j]<w)                 w = dis[v=j];         book[v] = 1;         for(int j = 0; j < G[v].size(); j++)             dis[G[v][j].v] = min(dis[G[v][j].v], w+G[v][j].w);     } }  int main(){     cin>>m;     for(int i = 1; i <= m; i++){         char a, b; int w;  cin>>a>>b>>w;         int x = a-'A', y = b-'A';         if(x>=0 && x<25)vis[x] = 1;         if(y>=0 && y<25)vis[y] = 1;         G[x].push_back(Edge(y,w));         G[y].push_back(Edge(x,w));     }     Dijkstra();     int v, w=0xffffff;     for(int i = 0; i < n; i++)         if(vis[i] && dis[i]<w)             w = dis[v=i];     cout<<(char)(v+'A')<<" "<<w<<"\n";     return 0; }
//数据太小, Floyd一番水 #include<iostream> #include<algorithm> using namespace std; int n = 60, m; int e[1010][1010], vis[1010]; int main(){     cin>>m;     for(int i = 0; i < n; i++)         for(int j = 0; j < n; j++)             e[i][j] = i==j ? 0 : 0xffffff;     for(int i = 0; i < m; i++){         char a, b; int w;  cin>>a>>b>>w;         int x = a-'A', y = b-'A';         if(x>=0 && x<25)vis[x] = 1;         if(y>=0 && y<25)vis[y] = 1;         //bugs数据可能有覆盖         e[x][y] = min(e[x][y], w);         e[y][x] = min(e[y][x], w);     }     for(int k = 0; k < n; k++)         for(int i = 0; i < n; i++)             for(int j = 0; j < n; j++)                 e[i][j] = min(e[i][j], e[i][k]+e[j][k]);     int ans2 = 0xffffff, ans1;     for(int i = 0; i < n; i++)if(vis[i] && e[i][(int)'Z'-'A']<ans2){         ans2 = e[i][(int)'Z'-'A'];         ans1 = i;     }     cout<<(char)(ans1+'A')<<" "<<ans2;     return 0; } 
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