Angular reactive forms pattern validator adding $ to regex and breaking validation

Question

I'm trying to validate a password with the following regex:
^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])(?=.{8,}).
Note that there is no terminating $ char, because that would prevent valid passwords from being accepted. (I'm not sure why the input field doesn't terminate the string).
However, Angular's Validators.pattern adds the end of string char. And therefore my valid passwords fail.
How do I prevent the pattern validator from adding the $?
I suppose I could roll my own password validator, but surely there is a better solution...?

EDIT: Passwords that should succeed:

• Test1234
• tEst1234
• tesT1234
• 1234Test
• 1234tesT
• t#St1234

Passwords that should fail:

• TEST1234
• test1234
• tEst123
• Test123
• testtest
• 12345678

Validator declaration:

this.password = new FormControl('', [Validators.required, Validators.pattern('^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])(?=.{8,})')]);
this.userForm.addControl('Password', this.password);

Answer 1

You may add a .* at the end, or even revamp the pattern a bit to convert one lookahead into a consuming pattern:

Validators.pattern('(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9]).{8,}')

Or, better, when using a regex for password validation, follow the principle of contrast:

Validators.pattern('(?=[^A-Z]*[A-Z])(?=[^a-z]*[a-z])(?=[^0-9]*[0-9]).{8,}')

Angular will add ^ and $ on both ends of the regex pattern, so the pattern will look like

^(?=[^A-Z]*[A-Z])(?=[^a-z]*[a-z])(?=[^0-9]*[0-9]).{8,}$

See the regex demo

Details

• ^ - start of string
• (?=[^A-Z]*[A-Z]) - at least 1 uppercase ASCII letter
• (?=[^a-z]*[a-z]) - at least 1 lowercase ASCII letter
• (?=[^0-9]*[0-9]) - at least 1 ASCII digit
• .{8,} - any 8 or more chars (other than line break chars)
• $ - end of string.