Linux getting all network interface names

问题

I need to collect all the interface names, even the ones that aren't up at the moment. Like ifconfig -a.

getifaddrs() is iterating through same interface name multiple times. How can I collect all the interface names just once using getifaddrs()?

回答1:

You could check which entries from getifaddrs belong to the AF_PACKET family. On my system that seems to list all interfaces:

struct ifaddrs *addrs,*tmp;

getifaddrs(&addrs);
tmp = addrs;

while (tmp)
{
    if (tmp->ifa_addr && tmp->ifa_addr->sa_family == AF_PACKET)
        printf("%s\n", tmp->ifa_name);

    tmp = tmp->ifa_next;
}

freeifaddrs(addrs);

回答2:

getifaddrs() will only return your interfaces addresses, not the interfaces themselves.

What if any of your interface has no address, or no address of the requested family, as suggested with the 'AF_PACKET' one ?

Here, an example where I’ve got a tunnel interface (with an OpenVPN connexion), and where I’m listing all entries from getifaddrs() for each of my network interfaces:

[0] 1: lo                address family: 17 (AF_PACKET) b4:11:00:00:00:01
                         address family: 2 (AF_INET)    address: <127.0.0.1>
                         address family: 10 (AF_INET6)  address: <::1>
[...]

[5] 10: tun0             address family: 2 (AF_INET)    address: <172.16.0.14>
[EOF]

Bam. No AF_PACKET on the "tun0" interface, but it DOES exist on the system.

You should, instead, use if_nameindex() syscall, which does exactly what you want. In other words, with no arguments, it returns a list of all interfaces on your system:

#include <net/if.h>
#include <stdio.h>

void main (void)
{
    struct if_nameindex *if_nidxs, *intf;

    if_nidxs = if_nameindex();
    if ( if_nidxs != NULL )
    {
        for (intf = if_nidxs; intf->if_index != 0 || intf->if_name != NULL; intf++)
        {
            printf("%s\n", intf->if_name);
        }

        if_freenameindex(if_nidxs);
    }

    return ;
}

And voilà.

回答3:

It seems that ifconfig -a only lists active interfaces (at least on Fedora 19). I know I have at least one more network card that I'm not seeing. Anyway, I get the same list as:

ls -1 /sys/class/net

Which could easily be done programatically.

回答4:

You are on the right track (it is getifaddrs). It returns each interface once per family, so you get eth0 for ipv4 and one for ipv6. If you just want each interface once you will have to uniq the output yourself.

回答5:

I thing this show you all interface, at least for me

ip link show

ls -1 /sys/class/net

only show interface name

lo
p4p1

回答6:

I need the main device that is being used by the system (assuming there is only one) such as eth0 wlan0 or whatever RHEL7 is trying to do...

The best I hacked together was this:

#!/bin/bash
# -- Get me the interface for the main ip on system

for each in $(ls -1 /sys/class/net) ;do 

    result=$(ip addr show $each | awk '$1 == "inet" {gsub(/\/.*$/, "", $2); print $2}' | grep "$(hostname -I | cut -d' ' -f1)")

    if [ ! -z "${result// }" ] && [ -d /sys/class/net/${each// } ] ;then
            echo "Device: $each IP: $result"
            break;
    fi

done

Sample output:

    ./maineth.sh  
    Device: enp0s25 IP: 192.168.1.6

来源：https://stackoverflow.com/questions/19227781/linux-getting-all-network-interface-names

标签

Linux

network-interface