问题
I see Why is -1/2 evaluated to 0 in C++, but -1 in Python? says integer division rounds towards infinity in Python, namely, floor is applied to the result.
I thought int(value) would also do something like floor, while I get int(-1.5) == -1 in practice, which was expected to be -2 in my mind.
So question is: why rules are inconsistent between integer division and function int()? Is there any reasonable explanation?
回答1:
int() removes the decimal component; it doesn't do any rounding. From the documentation:
If x is floating point, the conversion truncates towards zero.
For turning a float into an int this is entirely logical behaviour. This is not division, flooring or otherwise.
The // floor division operator otherwise clearly does floor, not truncate. In Python 2, for two integer operands, the / division also floors. The documentation again:
the result is that of mathematical division with the ‘floor’ function applied to the result
where math.floor() is documented as:
Return the floor of x as a float, the largest integer value less than or equal to x.
I see no inconsistency here; division floors, turning floats to integers truncates.
回答2:
Maybe round() with ndigits = 0 is more close to what you're expecting. But round() doesn't return an integer, but a float: see the documentation
来源：https://stackoverflow.com/questions/22100850/function-int-rounding-towards-negative-infinity-floor-or-zero