Prime numbers generator explanation? [duplicate]

旧巷老猫 提交于 2019-12-01 18:02:20

Starting with n True values in an array, with i enumerated from 3 to sqrt(n) by step of 2, if ith entry in the array is still True, set all entries from i^2 to the end of the array by step of 2*i to False (these will be the multiples of i).

All odd True entries that are left in the array in the end, are prime.

All thus found numbers, and 2, are all the prime numbers that exist below n.

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