How can I create an Delphi object from a class reference and ensure constructor execution?

假如想象 提交于 2019-11-26 13:03:54

问题


How can I create an instance of an object using a class reference, and ensure that the constructor is executed?

In this code example, the constructor of TMyClass will not be called:

type
   TMyClass = class(TObject)
     MyStrings: TStrings;
     constructor Create; virtual;
   end;

constructor TMyClass.Create;
begin
   MyStrings := TStringList.Create;
end;

procedure Test;
var
   Clazz: TClass;
   Instance: TObject;
begin
   Clazz := TMyClass;
   Instance := Clazz.Create;
end;

回答1:


Use this:

type
  TMyClass = class(TObject)
    MyStrings: TStrings;
    constructor Create; virtual;
  end;
  TMyClassClass = class of TMyClass; // <- add this definition

constructor TMyClass.Create;
begin
   MyStrings := TStringList.Create;
end;

procedure Test;
var
  Clazz: TMyClassClass; // <- change TClass to TMyClassClass
  Instance: TObject;
begin
   Clazz := TMyClass; // <- you can use TMyClass or any of its child classes. 
   Instance := Clazz.Create; // <- virtual constructor will be used
end;

Alternatively, you can use a type-casts to TMyClass (instead of "class of TMyClass").




回答2:


Alexander's solution is a fine one but does not suffice in certain situations. Suppose you wish to set up a TClassFactory class where TClass references can be stored during runtime and an arbitrary number of instances retrieved later on.

Such a class factory would never know anything about the actual types of the classes it holds and thus cannot cast them into their according meta classes. To invoke the correct constructors in such cases, the following approach will work.

First, we need a simple demo class (don't mind the public fields, it's just for demonstration purposes).

interface

uses
  RTTI;

type
  THuman = class(TObject)
  public
    Name: string;
    Age: Integer;

    constructor Create(); virtual;
  end;

implementation

constructor THuman.Create();
begin
  Name:= 'John Doe';
  Age:= -1;
end;

Now we instantiate an object of type THuman purely by RTTI and with the correct constructor call.

procedure CreateInstance();
var
  someclass: TClass;
  c: TRttiContext;
  t: TRttiType;
  v: TValue;
  human1, human2, human3: THuman;
begin
  someclass:= THuman;

  // Invoke RTTI
  c:= TRttiContext.Create;
  t:= c.GetType(someclass);

  // Variant 1a - instantiates a THuman object but calls constructor of TObject
  human1:= t.AsInstance.MetaclassType.Create;

  // Variant 1b - same result as 1a
  human2:= THuman(someclass.Create);

  // Variant 2 - works fine
  v:= t.GetMethod('Create').Invoke(t.AsInstance.MetaclassType,[]);
  human3:= THuman(v.AsObject);

  // free RttiContext record (see text below) and the rest
  c.Free;

  human1.Destroy;
  human2.Destroy;
  human3.Destroy;
end;

You will find that the objects "human1" and "human2" have been initialized to zero, i.e., Name='' and Age=0, which is not what we want. The object human3 instead holds the default values provided in the constructor of THuman.

Note, however, that this method requires your classes to have constructor methods with not parameters. All the above was not conceived by me but explained brillantly and in much more detail (e.g., the c.Free part) in Rob Love's Tech Corner.




回答3:


Please check if overriding AfterConstruction is an option.




回答4:


Your code slightly modified:

type
  TMyObject = class(TObject)
    MyStrings: TStrings;
    constructor Create; virtual;
  end;
  TMyClass = class of TMyObject;

constructor TMyObject.Create;
begin
  inherited Create;
  MyStrings := TStringList.Create;
end;

procedure Test; 
var
  C: TMyClass;
  Instance: TObject;
begin
   C := TMyObject;
   Instance := C.Create;
end;



回答5:


You can create an abstract method in base class, and call it in the constructor, and override in child classes to be executed when created from class reference.



来源:https://stackoverflow.com/questions/791069/how-can-i-create-an-delphi-object-from-a-class-reference-and-ensure-constructor

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