How can I get the text between tags using python SAX parser?

问题

What I need is just get the text of the corresponding tag and persist it into database. Since the xml file is big (4.5GB) I'm using sax. I used the characters method to get the text and put it in a dictionary. However when I'm printing the text at the endElement method I'm getting a new line instead of the text.

Here is my code:

def characters(self,content):
   text = unescape(content))
   self.map[self.tag]=text

def startElement(self, name, attrs):
   self.tag = name

def endElement (self, name)
   if (name=="sometag")
   print self.map[name]

Thanks in advance.

回答1:

The text in the tag is chunked by the SAX processor. characters might be called multiple times.

You need to do something like:

def startElement(self, name, attrs):
    self.map[name] = ''
    self.tag = name

def characters(self, content):
    self.map[self.tag] += content

def endElement(self, name):
    print self.map[name]

来源：https://stackoverflow.com/questions/2262577/how-can-i-get-the-text-between-tags-using-python-sax-parser