问题
I have a stream of incoming data that has interleaved real and imaginary integers. Converting these to complex64 values is the slowest operation in my program. This is my current approach:
import numpy as np
a = np.zeros(1000000, dtype=np.int16)
b = np.complex64(a[::2]) + np.complex64(1j) * np.complex64(a[1::2])
Can I do better without making a C extension or using something like cython? If I can't do better, what's my easiest approach using a technology like one of these?
回答1:
[~]
|1> import numpy as np
[~]
|2> a = np.zeros(1000000, dtype=np.int16)
[~]
|3> b = a.astype(np.float32).view(np.complex64)
[~]
|4> b.shape
(500000,)
[~]
|5> b.dtype
dtype('complex64')
来源:https://stackoverflow.com/questions/5658047/whats-the-fastest-way-to-convert-an-interleaved-numpy-integer-array-to-complex6