I have two structs as
struct collapsed {
char **seq;
int num;
};
struct data {
collapsed *x;
int num;
int numblocks;
int *blocksizes;
float *regmult;
float *learnmult;
};
I am passing it to my kernel as;
__global__ void KERNEL(data* X,...){
...
collapsed x = X->x[0]; // GIVES CUDA_EXPECTION_1:Lane Illegal Address
}
data X;
//init X
data *X_dev;
cudaMalloc((data **) & X_dev, sizeof(data));
cudaMemcpy(X_dev, &X, sizeof(data), cudaMemcpyHostToDevice);
KERNEL<<<...>>>(X_dev,...);
This code gives CUDA_EXPECTION_1:Lane Illegal Address in the kernel code. What is wrong or what is the right way to do it ? Any idea?
Robert Crovella
You're dereferencing a host pointer on the device.
X is a valid device pointer.
But when you copied the X struct to the device, you copied x along with it, which contains a host pointer. When you dereference that pointer:
collapsed x = X->x[0];
^ this is dereferencing the x pointer
the device code throws an error.
More detail is given here as well as instructions on how to fix it.
来源：https://stackoverflow.com/questions/16815705/passing-an-struct-including-a-pointer-to-another-struct-to-kernel-in-cuda