问题
I\'m trying to transform some XML into HTML using XSLT.
Problem:
I can\'t get it to work. Can someone tell me what I\'m doing wrong?
XML:
<ArrayOfBrokerage xmlns:i=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://www.test.com/\">
<Brokerage>
<BrokerageID>91</BrokerageID>
<LastYodleeUpdate>0001-01-01T00:00:00</LastYodleeUpdate>
<Name>E*TRADE</Name>
<Validation i:nil=\"true\" />
<Username>PersonalTradingTesting</Username>
</Brokerage>
</ArrayOfBrokerage>
XSLT:
<xsl:stylesheet version=\"1.0\" xmlns=\"http://www.test.com/\" xmlns:xsl=\"http://www.w3.org/1999/XSL/Transform\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xslFormatting=\"urn:xslFormatting\">
<xsl:output method=\"html\" indent=\"no\"/>
<xsl:template match=\"/ArrayOfBrokerage\">
<xsl:for-each select=\"Brokerage\">
Test
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
回答1:
You need to provide a namespace prefix in your xslt for the elements you are transforming. For some reason (at least in a Java JAXP parser) you can't simply declare a default namespace. This worked for me:
<xsl:stylesheet version="1.0" xmlns:t="http://www.test.com/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xslFormatting="urn:xslFormatting">
<xsl:output method="html" indent="no"/>
<xsl:template match="/t:ArrayOfBrokerage">
<xsl:for-each select="t:Brokerage">
Test
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
This will catch everything that is namespaced in your XML doc.
回答2:
How do you execute the transformation? Maybe you forgot to link the XSLT stylesheet to XML document using:
<?xml-stylesheet type="text/xsl" href="cdcatalog.xsl"?>
at the beginning of XML document. More explanation here.
来源:https://stackoverflow.com/questions/1730875/xslt-transform-xml-with-namespaces