问题
I am pulling JSON data from an API URL. The problem: Under FL there are duplicate KEYS: "val" and "content". I only need to pull specific KEYS.
Please excuse me if my formatting is not correct to SO standards.*
My question is posted below the json and code.
JSON FROM URL
{
"response": {
"result": {
"Leads": {
"row": [
{
"no": "1",
"FL": [
{
"val": "LEADID",
"content": "123"
},
{
"val": "SMOWNERID",
"content": "3232"
},
{
"val": "Lead Owner",
"content": "Cassie"
},
{
"val": "First Name",
"content": "Bobby"
},
{
"val": "Last Name",
"content": "Something"
},
{
"val": "Email",
"content": "email@gmail.com"
},
{
"val": "Mobile",
"content": "1111111111"
},
{
"val": "SMCREATORID",
"content": "0000003213"
},
{
"val": "Created By",
"content": "Cassie"
},
{
"val": "Created Time",
"content": "2019-04-03 15:14:05"
},
{
"val": "Modified Time",
"content": "2019-04-03 17:13:58"
},
{
"val": "Full Name",
"content": "Bobby Something"
},
{
"val": "Street",
"content": "123 Fake Rd"
},
{
"val": "City",
"content": "Fakecity"
},
{
"val": "State",
"content": "FK"
},
{
"val": "Zip Code",
"content": "11111"
},
{
"val": "Email Opt Out",
"content": "false"
},
{
"val": "Salutation",
"content": "Mr."
},
{
"val": "Last Activity Time",
"content": "2019-04-03 17:13:58"
},
{
"val": "Tag",
"content": "Tag"
},
{
"val": "Account Name",
"content": "Something"
},
{
"val": "Territory Manager",
"content": "Michael Something"
},
{
"val": "Territory Manager_ID",
"content": "321237000000291111"
},
{
"val": "Classification",
"content": "Something"
},
{
"val": "Area",
"content": "Zone 1"
},
{
"val": "Account Number",
"content": "32345"
}
]
}
]
}
},
"uri": "/crm/private/json/Leads/getRecords"
}
}
PHP CODE
$url = 'URL';
$data = file_get_contents($url);
$parsed = json_decode($data, true);
$eachEntry = $parsed['response']['result']['Leads']['row'];
foreach ($eachEntry as $entry) {
$FL = $entry['no'];
//printf('%s'.PHP_EOL, $FL);
printf("\n");
$entries = $entry['FL'];
foreach ($entries as $value) {
$val = $value['val'];
$content = $value['content'];
$out = $val." ".$content;
printf('%s'.PHP_EOL, $out);
printf("\n");
}
}
RESULTS
LEADID 123
SMOWNERID 3232
Lead Owner Cassie
First Name Bobby
Last Name Something
Email email@gmail.com
Mobile 1111111111
SMCREATORID 0000003213
Created By Cassie
Created Time 2019-04-03 15:14:05
Modified Time 2019-04-03 17:13:58
Full Name Bobby Something
Street 123 Fake Rd
City Fakecity
State FK
Zip Code 11111
Email Opt Out false
Salutation Mr.
Last Activity Time 2019-04-03 17:13:58
Tag Tag
Account Name Something
Territory Manager Michael Something
Territory Manager_ID 321237000000291111
Classification Something
Area Zone 1
Account Number 32345
QUESTION
How can I pull only the fields I have listed below in the example? And do not pull every field.
EXAMPLE
"val": "First Name",
"content": "Bobby"
,
"val": "Last Name",
"content": "Something"
,
"val": "Street",
"content": "123 Fake Rd"
,
"val": "City",
"content": "Fakecity"
,
"val": "State",
"content": "FK"
,
"val": "Zip Code",
"content": "11111"
EXPECTED OUTPUT
First Name Bobby
Last Name Bobby
Street 123 Fake Rd
City Fakecity
State FK
Zip Code 11111
Set JSON from URL into HTML Table
PHP JSON To Array Values Into HTML Table
回答1:
Just write the code to do what you describe. Simply don't print them if they're not in the list of fields you want.
$valuesIWant = ["First Name", "Last Name", "Street", "City", "State", "Zip Code"];
foreach ($eachEntry as $entry) {
$FL = $entry['no'];
//printf('%s'.PHP_EOL, $FL);
printf("\n");
$entries = $entry['FL'];
foreach ($entries as $value) {
$val = $value['val'];
$content = $value['content'];
if (in_array($val, $valuesIWant)) {
$out = $val." ".$content;
printf('%s'.PHP_EOL, $out);
printf("\n");
}
}
}
回答2:
you just need to maintain an array where you can provide all the options you want to fetch and check that in the loop like in the example below.
$url = 'URL';
$data = file_get_contents($url);
$parsed = json_decode($data, true);
$eachEntry = $parsed['response']['result']['Leads']['row'];
$required = ['First Name','Last Name','Street','City','State','Zip Code'];
foreach ($eachEntry as $entry) {
$FL = $entry['no'];
//printf('%s'.PHP_EOL, $FL);
printf("\n");
$entries = $entry['FL'];
foreach ($entries as $value) {
if(!in_array($value['val'],$required))
continue;
$val = $value['val'];
$content = $value['content'];
$out = $val." ".$content;
printf('%s'.PHP_EOL, $out);
printf("\n");
}
}
来源：https://stackoverflow.com/questions/55520394/php-json-decoding-to-array-to-grab-specific-key-values-all-fields-same-name