Build a repetitive selector within a Less loop

问题

I've seen various ways of looping in LESS, but I haven't found a way to build selectors (agglutinate would be the right term I guess).

For example, I'd like something like this:

.staticClass .repeatedClass .repeatedClass > .finalStaticClass{
    height: 20px;
}

Where .repeatedClass would be generated according to the loopcount. .staticClass and .finalStaticClass would be (as the name implies) static.

Also, the height property would be increased by 10 (or any given number) for every loopcount.

回答1:

I would go about it somehow in this manner:

.generateClasses (@index, @n, @in:"") when (@index > 0) {
    @concatenate: "@{in} .repeatedClass";
    @selector: ~".staticClass @{concatenate} > .finalStaticClass";
    @{selector}{ height: unit(@n,px) };
    .generateClasses((@index - 1), (unit(@n) + 10), @concatenate);
}
.generateClasses(0, @n, @in){};

.generateClasses(4, 10px);

Where you pass on to the next loop the concatenated generated classes and each time add another class. The @index is the counter for the loop, and @n is the value that you want to increase.

CSS output:

.staticClass  .repeatedClass > .finalStaticClass {
  height: 10px;
}
.staticClass  .repeatedClass .repeatedClass > .finalStaticClass {
  height: 20px;
}
.staticClass  .repeatedClass .repeatedClass .repeatedClass > .finalStaticClass {
  height: 30px;
}
.staticClass  .repeatedClass .repeatedClass .repeatedClass .repeatedClass > .finalStaticClass {
  height: 40px;
}

Edit - for older versions of Less:

in Less <= 1.3.3, you need to include the individual concatenating loops in a separate role (it is called .test in the example below), that confines the variable. Then you can loop through this, doing something along these lines:

.generateClasses (@index, @n, @in:"") when (@index > 0) {
    @concatenate: "@{in} .repeatedClass";
    @selector: ~".staticClass @{concatenate} > .finalStaticClass";
    .generateClasses((@index - 1), (unit(@n) + 10), @concatenate);
}
.generateClasses(0, @n, @in){};

.test(@i, @ni){
    .generateClasses(@i,@ni);
    @{selector} {
        height: @ni;
    }
}

.printClasses(@i:1,@ni:10px) when (@i > 0) {
    .test(@i,@ni*@i);
    .printClasses(@i - 1,@ni);
}

.printClasses(4);

output CSS will now be:

.staticClass  .repeatedClass .repeatedClass .repeatedClass .repeatedClass > .finalStaticClass {
  height: 40px;
}
.staticClass  .repeatedClass .repeatedClass .repeatedClass > .finalStaticClass {
  height: 30px;
}
.staticClass  .repeatedClass .repeatedClass > .finalStaticClass {
  height: 20px;
}
.staticClass  .repeatedClass > .finalStaticClass {
  height: 10px;
}

if you just need to generate a selector once at a time, you can skip the second loop and just call the .test() mixin wherever you need it.

回答2:

The proper solution would be:

.staticClass {
    .loop(5);
    .loop(@n, @i: 1) when (@i <= @n) {
        .repeatedClass {
            > .finalStaticClass {
                height: 10px * @i;
            }
            .loop(@n, @i + 1);
        }
    }
}

Demo.

来源：https://stackoverflow.com/questions/17695787/build-a-repetitive-selector-within-a-less-loop

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