Nodejs: How to catch an exception from middleware?

问题

I'm using node.js and the "less" compiler middleware:

app.configure(function() {
    // ...
    app.use(express.compiler({ src: __dirname + '/public', enable: ['less'] }))
    // ...
})

Now i've got a faulty .less-file, but I can't find any docs on how to get the error message. The page I receive is this:

<html>
  <head>
    <title>[object Object]</title>
    <style>
      /* css stuff */
    </style>
  </head>
  <body>
    <div id="wrapper">
      <h1>Connect</h1>

      <h2><em>500</em> [object Object]</h2>
      <ul id="stacktrace"></ul>
    </div>
  </body>
</html>

So that's not helpful. Anybody got an idea?

回答1:

Ah, ok, got it. The trick is to leave away the development errorHandler

app.configure('development', function() {
    // app.use(express.errorHandler({ dumpExceptions: true, showStack: true }));
});

It seems to swallow calls to app.error, so now this works:

app.error(function(err, req, res, next) {
    sys.puts("APP.ERROR:" + sys.inspect(err));
    next(err);
});

This shows the correct error instead of [object Object]

来源：https://stackoverflow.com/questions/4063764/nodejs-how-to-catch-an-exception-from-middleware

标签

node.js

express

less

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