问题
Suppose I want to apply a function to each row of a matrix. One of the function's arguments takes a vector. I would like to apply the first element of the vector to the first row, the second element to the second row, etc.
For example:
set.seed(123)
df<-matrix(runif(100), ncol=10)
var2 <- c(1:10)
MYFUNC <- function(x, Var=NA){
sum(x)/Var
}
I tried this:
apply(df, 1, function(x) MYFUNC(x, Var=var2))
But that gives me a 10x10 matrix with the function applied to each row & Var combination, whereas I'm only interested in the diagonal elements. I also looked into the mapply function, but I'm not sure how to apply it in this case.
Any help would be really appreciated.
回答1:
Mapply is definitely a possibility. This should work:
mapply(MYFUNC, x = as.data.frame(t(df)), Var = var2)
#V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
#5.0795111 2.8693537 1.8285747 1.3640238 0.8300597 0.6280441 0.7706310 0.6720132 0.5719003 0.4259674
The issue I think you were running into is that mapply takes either vectors or lists. In R matrices aren't lists, but data.frames are. All you need to do is transpose your matrix and convert to a data.frame and then mapply should work. Each column in a data.frame is an element in the list which is why we have to transpose it (so that each row will be mapped to each element in the vector).
回答2:
As there are two arguments that should be the corresponding rows and elements in matrix/vector respectively, we can loop through the sequence of rows, subset the data and apply the function
sapply(seq_len(nrow(df)), function(i) MYFUNC(df[i,], Var = var2[i]))
#[1] 5.0795111 2.8693537 1.8285747 1.3640238 0.8300597 0.6280441
#[7] 0.7706310 0.6720132 0.5719003 0.4259674
For the specific example, it can be vectorized with rowSums
rowSums(df)/var2
#[1] 5.0795111 2.8693537 1.8285747 1.3640238 0.8300597 0.6280441
#[7] 0.7706310 0.6720132 0.5719003 0.4259674
来源:https://stackoverflow.com/questions/43643665/r-apply-function-to-matrix-with-elements-of-vector-as-argument