Method reference with a full constructor call as a lambda expression in Java

问题

I have encountered a short time ago with a competitive answer better than mine that uses a quite new method reference to me as replacement of lambda.

Stream.generate(new AtomicInteger(1)::getAndIncrement)...

I looked the Oracle specifications about the Method references and there are defined 4 types:

• Reference to a static method ContainingClass::staticMethodName
• Reference to an instance method of a particular object containingObject::instanceMethodName
• Reference to an instance method of an arbitrary object of a particular type ContainingType::methodName
• Reference to a constructor ClassName::new

I struggle with categorizing this one. I haven't found any question on SO or anything relevant explained in the docs. How would be this translated to an anonymous class?

My suspicion is:

IntStream.generate(new IntSupplier() {

    AtomicInteger atom = new AtomicInteger(1);

    @Override
    public int getAsInt() {
        return atom.getAndIncrement();
    }
})....

... I don't understand how is this possible. At first sight, I would guess the expression is:

IntStream.generate(new IntSupplier() {

    @Override
    public int getAsInt() {
        return new AtomicInteger(1).getAndIncrement();
    }
})....

... yet this is nothing else than () -> new AtomicInteger(1).getAndIncrement().

Where is this kind of expression defined and how it exactly would be rewritten in the lambda/anonymous class?

回答1:

Well new AtomicInteger(1) returns an instance, so it's the second one. The exact details of how this is translated are implementation specific, but it's a single instance created and this is back-ed up by the JLS 15.13.3

First, if the method reference expression begins with an ExpressionName or a Primary, this subexpression is evaluated

In plain english, the part before :: is evaluated when it's declaration is first encountered.

Your assumption how this is translated is almost correct, it's like generating an instance outside of the function itself and using that - since it is effectively final, this is permitted.

回答2:

It's simply the second type: a reference to a method of a specific object, there's no additional logic behind the curtain.

回答3:

You can replace

Stream.generate(new AtomicInteger(1)::getAndIncrement)...

with

AtomicInteger containingObject = new AtomicInteger(1);
Stream.generate(containingObject::getAndIncrement)...

i.e. this method reference falls into the second category of method references - Reference to an instance method of a particular object.

You should note that the AtomicInteger instance creation is not part of the implementation of the IntSupplier. The Java 7 equivalent would be:

AtomicInteger aint = new AtomicInteger(1);
IntStream.generate(new IntSupplier() {

    @Override
    public int getAsInt() {
        return aint.getAndIncrement();
    }
})...

.

来源：https://stackoverflow.com/questions/53591305/method-reference-with-a-full-constructor-call-as-a-lambda-expression-in-java