Get domain without subdomain from a URL

时光毁灭记忆、已成空白 提交于 2019-12-01 02:40:13

I know this is a few years late but if anyone stumbles across this question try the following:

InternetDomainName.from("subhost.example.co.uk").topPrivateDomain().name

The above will return example.co.uk.

Not sure if the above answer is correct:

InternetDomainName.from("test.blogspot.com").topPrivateDomain() -> test.blogspot.com

This works better in my case:

InternetDomainName.from("test.blogspot.com").topDomainUnderRegistrySuffix() -> blogspot.com

Details: https://github.com/google/guava/wiki/InternetDomainNameExplained

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!