Inconsistent accessibility: base class is less accessible than class

空扰寡人 提交于 2019-12-01 02:26:11

You don't and you can't.

If you want to expose the class as public, the base-type must be public. One other option is to have a public interface, and only expose the type via the interface (presumably with a factory method somewhere for creating instances).

One final option is to encapsulate the base-class rather than inherit it.

Make it public, make all constructors internal (if you're using the default constructor, add a parameterless constructor to override that).

Then while public and not sealed, it can't be sub-classed by external code.

Just to clarify what I was saying in comments on @Marc Gravel's answer you could

public ChildClass : ParentClass
{

}

public ParentClass
{
   internal void MethodIdontWantToExpose()
  {

  }

}

That said an interface is probably the best solution

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