How to compare two case insensitive strings?

故事扮演 提交于 2019-12-01 02:18:17

问题


i have 2 string objects containing same string but case is different,now i wanna compare them ignoring the case sensitivity,how to do that??here is the code...

#import <Foundation/Foundation.h>
void main()  
{  
    NSString *myString1 = @"mphasis";  
    NSString *myString2 = @"MPHASIS";
    if ([myString1 caseInsenstiveCompare:myString2])  
    {  
        NSLog (@"ITS EQUAL");  
    }  
    else  
    {   
        NSLog (@"ITS NOT EQUAL");  
    }  
}  

回答1:


If you look up caseInsensitiveCompare: in the docs you'll see that it returns an NSComparisonResult rather than a BOOL. Look that up in the docs and you'll see that you probably want it to be NSOrderedSame. So

if ([myString1 caseInsensitiveCompare:myString2] == NSOrderedSame)

should do the trick. Or just compare the lowercase strings like Robert suggested.




回答2:


Just use lowercaseString on both of the strings and then compare them as you would using a normal string equality check. It will still be O(n) so no big deal.




回答3:


I would rather suggest to add a category on NSString:

- (BOOL)isEqualIgnoreCaseToString:(NSString *)iString {
    return ([self caseInsensitiveCompare:iString] == NSOrderedSame);
}

With this you can simply call:

[myString1 isEqualIgnoreCaseToString:myString2];



回答4:


To save a method call, I used a macro via a #define:

#define isEqualIgnoreCaseToString(string1, string2) ([string1 caseInsensitiveCompare:string2] == NSOrderedSame)

Then call:

(BOOL) option = isEqualIgnoreCaseToString(compareString, toString);



回答5:


A simple one, convert both strings in same case.Here i'm converting it to lower case and then checking it.

if ([[myString1 lowercaseString] [myString2 lowercaseString]])
{
 // same
}


来源:https://stackoverflow.com/questions/5089997/how-to-compare-two-case-insensitive-strings

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!