Format: add trailing spaces to character output to left-justify

Question

How do you format a string to have constant width and be left-justified? There is the Aw formatter, where w denotes desired width of character output, but it prepends the spaces if w > len(characters), instead of appending them.

When I try

44 format(A15)
   print 44, 'Hi Stack Overflow'

I get

>        Hi Stack Overflow<

instead of

>Hi Stack Overflow        <

Is there any simple Fortran formatting solution that solves this?

Answer 1

As noted in the question, the problem is that when a character expression of length shorter than the output field width the padding spaces appear before the character expression. What we want is for the padding spaces to come after our desired string.

There isn't a simple formatting solution, in the sense of a natural edit descriptor. However, what we can do is output an expression with sufficient trailing spaces (which count towards the length).

For example:

print '(A50)', 'Hello'//REPEAT(' ',50)

or

character(50) :: hello='Hello'
print '(A50)', hello

or even

print '(A50)', [character(50) :: 'hello']

That is, in each case the output item is a character of length (at least) 50. Each will be padded on the right with blanks.

If you chose, you could even make a function which returns the extended (left-justified) expression:

print '(A50)', right_pad('Hello')

where the function is left as an exercise for the reader.

Answer 2

To complete @francescalus excellent answer for future reference, the proposed solution also works in case of allocatables in place of string literals:

character(len=:), allocatable :: a_str

a_str = "foobar"

write (*,"(A,I4)") a_str, 42
write (*,"(A,I4)") [character(len=20) :: a_str], 42

will output

foobar  42
foobar                42

Answer 3

a bit ugly but you can concatenate a blank string:

    character*15 :: blank=' '
    print 44, 'Hi Stack Overflow'//blank

Answer 4

program test ! Write left justified constant width character columns 
! declare some strings.
character(len=32) :: str1,str2,str3,str4,str5,str6 
! define the string values.
str1 = "     Nina "; str2 = "       Alba  " ; str3 = "        blue   " 
str4 = "  Jamil   "; str5 = "   Arnost "    ; str6 = " green             "
write(*,'(a)') "123456789012345678901234567890"
! format to 3 columns 10 character wide each.
! and adjust the stings to the left.
write(*,'(3(a10))') adjustl(str1), adjustl(str2), adjustl(str3) 
write(*,'(3(a10))') adjustl(str4), adjustl(str5), adjustl(str6) 
end program test

 $ ./a.out
123456789012345678901234567890
Nina      Alba      blue 
Jamil     Arnost    green

adjustL() moves leading spaces to the end of the string.

Answer 5

I suggest that you do not limit the number of output characters.

Change it to the following will work:

44 format(A)
 print 44, 'Hi Stack Overflow'