NodeList.prototype.forEach = Array.prototype.forEach;

痴心易碎 提交于 2019-11-30 22:56:00

问题


Do you see any problems with the following:

NodeList.prototype.forEach = Array.prototype.forEach;

Normally forEach is just a property of arrays, but by setting it as a property of all NodeLists as well, there's no need to convert a NodeList to an array before you can loop through its nodes with forEach.


回答1:


It's often not a good idea to extend the functionality of DOM through prototypes, especially in older versions of IE (article).

However, you can simply use Array.prototype.forEach even without adding it to the prototype chain or converting your NodeList into an array:

var list = document.querySelectorAll(".some.query");
Array.prototype.forEach.call(list, function(el){ /* ... */ });

/* or */
var forEach = function(ctn, callback){
    return Array.prototype.forEach.call(ctn, callback);
}
forEach(list, function(el){ /* ... */ });

See also MDN: Why can't I use forEach or map on a NodeList.




回答2:


If you're working on a library that will be used by other people then it's not a good idea to do this.

If it's just your own code (i.e.. a website) then I guess it's no big deal. You should probably guard it though because in the future browsers will support NodeList.prototype.forEach natively (Chrome does already).

if (!NodeList.prototype.forEach) {
  NodeList.prototype.forEach = Array.prototype.forEach;
}



回答3:


As Zeta mentioned, it would be better to use a convenience function. This version, however, will allow you to give it context.

var forEach = function(list, callback, context){
  return Array.prototype.forEach.call(list, callback, context);
};


来源:https://stackoverflow.com/questions/15267295/nodelist-prototype-foreach-array-prototype-foreach

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