list排序

Collections.sort(list,(o1,o2) -> {
    String name1=o1.get("name").toString();
    String name2=o2.get("name").toString();   
    return name1.compareTo(name2)
});

 

Collections.sort(list,(o1,o2) ->Integer.compare(Integer.valueOf(o2.get("value").toString()),Integer.valueOf(o1.get("value").toString())));

来源：https://my.oschina.net/u/3677751/blog/3112714