Quite simply in PHP I have a date of 8th January 2011, in the format 08-01-11 - when I run this into strtotime and convert it back into a different date format, it reverts back to 1st August 2011 - not ideal!
Is there any easy way around this, rather than having to place everything into different arrays/variables and back again?
Thank you!
strtotime() works with US dates only:
The function expects to be given a string containing a US English date format and will try to parse that format into a Unix timestamp.
You would have to either rearrange the date format or use date_parse_from_format() (PHP 5.3+) to parse the UK style string.
The perfect solution would be for the US to use the correct date format in the first place... ;0)
I do this to get around it:
$date = "31/12/2012";
$bits = explode('/',$date);
$date = $bits[1].'/'.$bits[0].'/'.$bits[2];
$date is now strtotimeable
From the PHP manual:
"Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD) dates or DateTime::createFromFormat() when possible."
I replaced slashes with dashes and then strtotime worked as expected for UK dates.
来源:https://stackoverflow.com/questions/4163641/php-using-strtotime-with-a-uk-date-format-dd-mm-yy