Inconsistent use of tabs and spaces in indentation

给你一囗甜甜゛ 提交于 2019-11-26 11:29:56

问题


def contains_sequence(dna1, dna2):
    \'\'\' (str, str) -> bool

    Return True if and only if DNA sequence dna2 occurs in the DNA sequence
    dna1.

    >>> contains_sequence(\'ATCGGC\', \'GG\')
    True
    >>> contains_sequence(\'ATCGGC\', \'GT\')
    False

    \'\'\'
    b=False
    len2=len(dna2)
    i=0
    for j in dna1:
        temp=dna1[i:i+len2]
        if temp == dna2:
            b=True
        i=i+1
    return b

I am new to Python. The program pasted above gives me an error \"Inconsistent use of tabs and spaces in indentation\" at line \"if temp == dna2:\" specifically. Can someone please help me out in finding out how the indentation is incorrect?


回答1:


It means you have mixed up spaces and tabs in the indentation. You have to fix that to be consistent with either tabs or spaces.




回答2:


If you look carefully at the lines

    temp=dna1[i:i+len2]
    if temp == dna2:

in your code, you will see that the "space" at the beginning of each line is "constructed" differently. In one case it uses tabs and in the other spaces, or, if both have tabs and spaces then they are used in different combinations.

You can examine this by placing your cursor at the beginning of each line and using the right-arrow key to "walk" your way through the characters. You'll see that the cursor moves differently on each line.

To fix, delete the tabs and spaces at the beginning of each line and re-insert them with the same characters on each line.

To avoid in the future, train yourself to use only the tab key OR the space key to indent, and consider setting your editor to automatically convert tabs to spaces.




回答3:


Assuming you have a "good" IDE, it's best to set the tab key to make 4 spaces instead of a "tab", that way you have less problems, and it's good practice, for when you will work with other people.




回答4:


According to the your Doc strings

your code:

b=False
len2=len(dna2)
i=0
for j in dna1:
    temp=dna1[i:i+len2]
    if temp == dna2:
        b=True
    i=i+1
return b

This much Big code can be simplified to one line

return dna1.find(dna2)>=0

Also if u are not good with indentations in 'vim' editor its good to practice in IDLE3



来源:https://stackoverflow.com/questions/12989171/inconsistent-use-of-tabs-and-spaces-in-indentation

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