In t-sql, is there a way to do pattern matching in a like statement such that you can search for 1 or more characters in a given set?
To be specific, I'm trying to come up with a LIKE statement that will return strings that begin with 1 or more letters and end in 1 or more numbers.
So these strings should match:
- abcd1234
- a1
- abcdef2
- ab123456
And these strings should not match:
- abcd
- 1234
- abcd1234abcd
- 1abcd1
I know you can use the % wildcard to match a string of 0 or more characters, and you can use brackets[] to match a single character in a given set. But is there any way to combine those so that I can match on 1 or more characters in a given set?
Something like this would be nice, but of course doesn't work:
WHERE ColumnName LIKE '[%a-z][%0-9]'
Does anyone know of a solution to this problem? Or is it just not possible in SQL Server?
Thanks, Jim
Like pattern matching is very limited, it does not allow for normal regular expressions.
See here for details.
For your needs use:
WHERE ColumnName LIKE '[a-z]%[0-9]'
This will match any letter followed by anything, followed by a number. SQL will enforce that the letter and number are at the two ends of the string because there is no pattern or literal character before or after our [] match set.
If you want to use Regex and have permissions, you can write a user defined function to give yourself access to the Regular Expressions parser on the SQL server's .NET CLR:
http://msdn.microsoft.com/en-us/magazine/cc163473.aspx (SQL 2005 and higher)
来源：https://stackoverflow.com/questions/27569788/sql-server-combining-and-wildcards-in-like-statement