Why does passing object reference arguments to thread function fails to compile?

♀尐吖头ヾ 提交于 2019-11-26 11:24:31

Threads copy their arguments (think about it, that's The Right Thing). If you want a reference explicitly, you have to wrap it with std::ref (or std::cref for constant references):

std::thread t(foo, std::ref(std::cout));

(The reference wrapper is a wrapper with value semantics around a reference. That is, you can copy the wrapper, and all copies will contain the same reference.)

As usual, this code is only correct as long as the object to which you refer remains alive. Caveat emptor.

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!