Thread Error: The Handle is Invalid (6) when trying to Free a suspended thread

混江龙づ霸主 提交于 2019-11-30 13:42:07

You can't set FreeOnTerminate to True and call Free on the thread instance. You have to do one or the other, but not both. As it stands your code destroys the thread twice. You must never destroy an object twice and of course when the destructor runs for the second time, errors occur.

What happens here is that since you created the thread suspended, nothing happens until you explicitly free the thread. When you do that the destructor resumes the thread, waits for it to complete. This then results in Free being called again because you set FreeOnTerminate to True. This second call to Free closes the handle. Then you return to the thread proc and that calls ExitThread. This fails because the thread's handle has been closed.

As Martin points out in the comment you must not create TThread directly since the TThread.Execute method is abstract. Also, you should not use Resume which is deprecated. Use Start to begin execution of a suspended thread.

Personally I don't like to use FreeOnTerminate. Using this feature results in the thread being destroyed on a different thread from which it was created. You typically use it when you want to forget about the instance reference. That then leaves you uncertain as to whether or not the thread has been destroyed when your process terminates, or even whether it is terminating and freeing itself during process termination.

If you must use FreeOnTerminate then you need to make sure that you don't call Free after having set FreeOnTerminate to True. So the obvious solution is to set FreeOnTerminate to True immediately before after calling Start and then forget about the thread instance. If you have any exceptions before you are ready to start then you can safely free the thread then since you FreeOnTerminate would still be False at that point.

Thread := TMyThread.Create(True);
Try
  //initialise thread object
Except
  Thread.Free;
  raise;
End;
Thread.FreeOnTerminate := True;
Thread.Start;
Thread := nil;

A more elegant approach would be to move all the initialisation into the TMyThread constructor. Then the code would look like this:

Thread := TMyThread.Create(True);
Thread.FreeOnTerminate := True;
Thread.Start;
Thread := nil;

The situation is very complicated in your case.

First, you does not actually free a suspended thread; a thread is resumed in destructor:

  begin
    Terminate;
    if FCreateSuspended then
      Resume;
    WaitFor;
  end;

Since Terminate is called before Resume, the Execute method never runs, and thread terminates immediately after being resumed:

  try
    if not Thread.Terminated then
    try
      Thread.Execute;
    except
      Thread.FFatalException := AcquireExceptionObject;
    end;
  finally
    Result := Thread.FReturnValue;
    FreeThread := Thread.FFreeOnTerminate;
    Thread.DoTerminate;
    Thread.FFinished := True;
    SignalSyncEvent;
    if FreeThread then Thread.Free;

Now look at the last line - you call destructor (Thread.Free) from destructor itself! Fantastic bug!


To answer your questions:

  1. You just can't use FreeOnTerminate:= True in your code;
  2. You should ask Embarcadero why TThread is designed so; my guess - some code (DoTerminate method) should be executed in thread context while thread terminates.

You can send a feature request to QC: add FFreeOnTerminate:= False to TThread.Destroy implementation:

destructor TThread.Destroy;
begin
  FFreeOnTerminate:= False;
// everything else is the same
  ..
end;

That should prevent recursive desctructor call and make your code valid.

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