问题
Consider the following snippet of python code
class A(object):
def __init__(self, a):
self.a = a
class B(A):
def __init__(self, a, b):
super(B, self).__init__(a)
self.b = b
class C(A):
def __init__(self, a, c):
super(C, self).__init__(a)
self.c = c
class D(B, C):
def __init__(self, a, b, c, d):
#super(D,self).__init__(a, b, c) ???
self.d = d
I am wondering how can I pass a, b and c to corresponding base classes' constructors.
回答1:
Well, when dealing with multiple inheritance in general, your base classes (unfortunately) should be designed for multiple inheritance. Classes B and C in your example aren't, and thus you couldn't find a proper way to apply super in D.
One of the common ways of designing your base classes for multiple inheritance, is for the middle-level base classes to accept extra args in their __init__ method, which they are not intending to use, and pass them along to their super call.
Here's one way to do it in python:
class A(object):
def __init__(self,a):
self.a=a
class B(A):
def __init__(self,b,**kw):
self.b=b
super(B,self).__init__(**kw)
class C(A):
def __init__(self,c,**kw):
self.c=c
super(C,self).__init__(**kw)
class D(B,C):
def __init__(self,a,b,c,d):
super(D,self).__init__(a=a,b=b,c=c)
self.d=d
This can be viewed as disappointing, but that's just the way it is.
回答2:
Unfortunately, there is no way to make this work using super() without changing the Base classes. Any call to the constructors for B or C is going to try and call the next class in the Method Resolution Order, which will always be B or C instead of the A class that the B and C class constructors assume.
The alternative is to call the constructors explicitly without the use of super() in each class.
class A(object):
def __init__(self, a):
object.__init__()
self.a = a
class B(A):
def __init__(self, a, b):
A.__init__(self, a)
self.b = b
class C(object):
def __init__(self, a, c):
A.__init__(self, a)
self.c = c
class D(B, C):
def __init__(self, a, b, c, d):
B.__init__(self, a, b)
C.__init__(self, a, c)
self.d = d
There is still a downside here as the A constructor would be called twice, which doesn't really have much of an effect in this example, but can cause issues in more complex constructors. You can include a check to prevent the constructor from running more than once.
class A(object):
def __init__(self, a):
if hasattr(self, 'a'):
return
# Normal constructor.
Some would call this a shortcoming of super(), and it is in some sense, but it's also just a shortcoming in multiple inheritance in general. Diamond inheritance patterns are often prone to errors. And a lot of the workarounds for them lead to even more confusing and error-prone code. Sometimes, the best answer is to try and refactor your code to use less multiple inheritance.
来源:https://stackoverflow.com/questions/34884567/python-multiple-inheritance-passing-arguments-to-constructors-using-super