问题
I developed a site that uses tags (key words) in order to categorize photographs. Right now, what I have in my MySQL database is a table with the following structure:
image_id (int)
tag (varchar(32))
Every time someone tags an image (if the tag is valid and has enough votes) it's added to the database. I think that this isn't the optimal way of doing things since now that I have 5000+ images with tags, the tags table has over 40000 entries. I fear that this will begin to affect performance (if it's not already affecting it).
I considered this other structure thinking that it'd be faster to fetch the tags associated to a particular image but then it looks horrible for when I want to get all the tags, or the most popular one for instance:
image_id (int)
tags (text) //comma delimited list of tags for the image
Is there a correct way of doing this or are both ways more or less the same? Thoughts?
回答1:
Use a many-to-many table to link a TAG record to an IMAGE record:
IMAGE
DROP TABLE IF EXISTS `example`.`image`;
CREATE TABLE `example`.`image` (
`image_id` int(10) unsigned NOT NULL auto_increment,
PRIMARY KEY (`image_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
TAG
DROP TABLE IF EXISTS `example`.`tag`;
CREATE TABLE `example`.`tag` (
`tag_id` int(10) unsigned NOT NULL auto_increment,
`description` varchar(45) NOT NULL default '',
PRIMARY KEY (`tag_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
IMAGE_TAG_MAP
DROP TABLE IF EXISTS `example`.`image_tag_map`;
CREATE TABLE `example`.`image_tag_map` (
`image_id` int(10) unsigned NOT NULL default '0',
`tag_id` int(10) unsigned NOT NULL default '0',
PRIMARY KEY (`image_id`,`tag_id`),
KEY `tag_fk` (`tag_id`),
CONSTRAINT `image_fk` FOREIGN KEY (`image_id`) REFERENCES `image` (`image_id`),
CONSTRAINT `tag_fk` FOREIGN KEY (`tag_id`) REFERENCES `tag` (`tag_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
回答2:
You can make a tags table which is just an id and tag with a unique constraint on tag and then photo_tags table which has tag_id and photo_id. Insert a tag into the tags table only if it doesn't already exist.
Then you will be querying by a pk instead of varchar text comparison when doing queries like how many photos are tagged with a certain tag.
回答3:
In multi tag search query you will have to hit every tag that is requested. Hence image tag set I has to be a superset of the request tag set U.
I >= U
To implement this complex comparison in SQL is a bit of challenge as each of the image has to be qualified individually. Given that tags are unique set per image:
SELECT i.* FROM images AS i WHERE {n} = (
SELECT COUNT(*)
FROM image_tags AS t
WHERE t.image_id = i.image_id
AND t.tag IN ({tag1}, {tag2}, ... {tagn})
)
Schema:
CREATE TABLE images (
image_id varchar NOT NULL,
PRIMARY KEY (image_id)
)
CREATE TABLE image_tags (
image_id varchar NOT NULL,
tag varchar NOT NULL,
PRIMARY KEY (image_id, tag)
)
来源:https://stackoverflow.com/questions/3508207/best-practice-for-storing-tags-in-a-database